获取（串＃）函数跳过第一个获得请求 [英] Gets(string#) function skipping first gets request

问题描述

我的工作我个人的休闲和学习的项目。部分原因是这样的：

I'm working on a project for my own personal leisure and learning. Part of it looks like this:

 #include<stdio.h>
 #include<string.h>
 wgame()
 {
 char string3[12], string2[12], string1[12], string4[12], string5[12];
 memset (string1, 0, 11);
 memset (string2, 0, 11);
 memset (string3, 0, 11);
 memset (string4, 0, 11);
 memset (string5, 0, 11);
 printf("reference C correct\n");
 printf("Okay, so you want a game. Here's one for you\n\n\n");
 printf("This is a word game.\n\n   A noun is a person place or thing.\n   A verb is 
 something that you can get up and do.\n   A subject is what the conversation is about.\n");
 printf("Go ahead, type a subject:\n");
 gets(string3);
 printf("That's a good one. Now, type a verb:\n");
 gets(string2);
 printf("How about another:\n");
 gets(string4);
 printf("Really? Okay. Now, type in a noun:\n");
 gets(string1);
 printf("Cool. How about typing another noun:\n");
 gets(string5);
 printf("Allright, here's how your words fit into this game:\n\n\n\n\n");
 printf("When the %s was %s the %s %s all the other %s", string1, 
 string2, string3, string4, string5);
 return 4;

 }

我的问题是输出跳过第一个获取（串＃），并继续到
接下来的printf（）。谁能告诉我这是为什么？

My problem is that the output is skipping over the first "gets(string#)" and proceeding to the next "printf()". Can someone tell me why this is?

推荐答案

这可能是因为 wgame 你正在做一些之前 scanf函数留下一个 \\在标准输入输出缓冲器n 。

It's likely that before wgame you are doing some scanf that leaves a \n in the stdio buffer.

下面是你应该做的几件事情：

Here are a few things you should do:

• 请不要混用 scanf函数和获得


• 请不要使用获得。使用与fgets


• 不要听人提示 fflush（标准输入）。这是错误

• Don't mix scanf and gets
• Don't use gets. Use fgets
• Don't listen to people suggesting fflush(stdin). It's wrong.

使用非常谨慎和节制，你可以使用：

With great care and moderation, you could use:

/* Right before `wgame` begins. */
while((c = getchar()) != '\n' && c != EOF)
    ;

不过，要知道它应谨慎使用，丢弃用户的输入是很危险的。

However, be aware it should be used sparingly, discarding user input is dangerous.

阅读Ç常见问题解答关于这个问题，和的解释约冲洗标准输入

Read this C FAQ on the subject, and an explanation about flushing stdin.

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