错误：`itoa`不是在这个范围内声明 [英] error: `itoa` was not declared in this scope

问题描述

我有如下称为itoa.cpp一个示例C文件：

I have a sample c file called itoa.cpp as below:

#include <stdio.h>
#include <stdlib.h>

int main ()
{
  int i;
  char buffer [33];
  printf ("Enter a number: ");
  scanf ("%d",&i);
  itoa (i,buffer,10);
  printf ("decimal: %s\n",buffer);
  return 0;
}

当我编译上面code与下面的命令：

When i compile the above code with the below command:

gcc itoa.cpp -o itoa

我得到这个错误：

i am getting this error:

[root@inhyuvelite1 u02]# gcc itoa.cpp -o itoa
itoa.cpp: In function "int main()":
itoa.cpp:10: error: "itoa" was not declared in this scope

什么是错的这个code？如何摆脱这种？

What is wrong in this code? How to get rid of this?

推荐答案

itoa不是ANSI C标准，你应该避免。下面是一些滚你自己的实现，如果你真的想这样用：

itoa is not ansi C standard and you should probably avoid it. Here are some roll-your-own implementations if you really want to use it anyway:

http://www.strudel.org.uk/itoa/

如果您在内存中字符串格式化需要，更好的选择是使用的snprintf。从你的工作例如：

If you need in memory string formatting, a better option is to use snprintf. Working from your example:

#include <stdio.h>
#include <stdlib.h>

int main ()
{
  int i;
  char buffer [33];
  printf ("Enter a number: ");
  scanf ("%d",&i);
  snprintf(buffer, sizeof(buffer), "%d", i);
  printf ("decimal: %s\n",buffer);
  return 0;
}

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