C90:我如何在全球范围初始化这个结构的C时不C99扩展 [英] C90: How do I globally initialize this struct in C without C99 extensions
问题描述
我不知道初始化这个结构的最佳方式是什么C90,同时仍保持平整。
在我的头文件,称它为test.h,我有以下结构定义的:
结构s_test_cfg {
字符* A [3];
炭* B [3];
字符* C [3];
}
然后我把它声明为一个外部的结构,这样我可以在.c文件全局初始化:
的extern结构s_test_cfg test_cfg;
现在在我的.c文件,我希望能够宣布这样的全球性(显然就是我要写在C90不支持):
结构s_test_cfg test_cfg =
{.A = {一,B,C},\\
.B = {D,E,F},\\
.C = {G,H,I}};
这显然使得它非常整齐而透明的,以你想要做什么。我怎样才能初始化在我的C文件中的全局结构,这也是那样干净这个语法?谢谢你。
结构s_test_cfg test_cfg = {
{一,B,C},/ * .A * /
{D,E,F} / * * .B /
{G,H,I} / * * .C /
};
也许是最简洁的选项(短让自己一个C99编译器,GCC和英特尔C都支持C99)。
I was wondering what the best way to initialize this struct is with C90, while still keeping it neat.
In my header file, call it test.h, I have the following struct defined:
struct s_test_cfg{
char *a[3];
char *b[3];
char *c[3];
}
Then I have it declared as an extern struct so that I can initialize it globally in the .c file:
extern struct s_test_cfg test_cfg;
Now in my .c file, I want to be able to declare something like this globally (obviously what I'm about to write is unsupported in C90):
struct s_test_cfg test_cfg =
{ .a = {"a", "b", "c"},\
.b = {"d", "e", "f"},\
.c = {"g", "h", "i"} };
This obviously makes it very neat and transparent as to what you're trying to do. How can I initialize the global struct in my C file that is also as clean as this syntax? Thanks.
struct s_test_cfg test_cfg = {
{ "a", "b", "c" }, /* .a */
{ "d", "e", "f" }, /* .b */
{ "g", "h", "i" }, /* .c */
};
is probably the cleanest option (short of getting yourself a C99 compiler; GCC and Intel C both support C99).
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