关于默认的C结构值，你看这个code？ [英] About default C struct values, what about this code?

问题描述

我试图创建具有默认值结构。我不知道如何做到这一点，因为每个code，我看到，大约是初始化，我会为它的自然的方式一样...

I'm trying to create structs with default values. I don't know how to accomplish this because every code that I see, is about initialising, and I would it for the natural way like...

struct stuff {
  int stuff_a = 1;
  int stuff_b = 2...
  ...and so on...
};

和细算一下，我发现这个（C ++）code：

and looking about, I found this (C++) code:

struct a{   a() : i(0), j(0) {};  INT i;   INT j;}

我从来没有见过这样的事为C.请帮助我理解它;我觉得这是非常好的！

I never saw anything like this for C. Please, help me to understand it; I think that it is very nice!

更新：等一下，我在问关于C !!!!为什么改变了我的问题吗？如果在C是不可能只是说...我不知道C ++，我不知道这是关于C ++ ...

UPDATE: Wait, I'm asking about C!!!! Why changed my question? If that is not possible in C just say... I don't know C++, I didn't know that was about C++...

推荐答案

如果您想设置一个struct对象一气呵成和你有C99编译，试试这个：

If you want to set a struct object in one go and you have a C99 compiler, try this:

struct stuff {
    int stuff_a;
    int stuff_b;
    // and so on...
};

struct stuff foo;
/* ... code ... */
foo = (struct stuff){.stuff_b = 42, .stuff_a = -1000};

另外，用C89编译器，你必须通过一个每个成员来设置：

Otherwise, with a C89 compiler, you have to set each member one by one:

foo.stuff_b = 42;
foo.stuff_a = -1000;

---

运行例如@ ideone： http://ideone.com/1QqCB

原线

struct a{   a() : i(0), j(0) {}   INT i;   INT j;}

在C语法错误。

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