在C静态结构的成员变量 [英] The member variable of a static struct in C

问题描述

我有一个静态的结构在C语言中的成员变量的问题。

I have a question about the member variables of static struct in C language.

有人说，我们可以声明一个静态结构，但在C，结构不具备静态成员像C ++类，这是什么意思？如果我宣布一个静态的结构，什么是成员的状态变量？可以有人帮助我在这？

Someone said we can declare a static struct, but in C, struct do not have the static members like class in C++, what does this mean? If I declare a static struct, what is the status of the members variable? can some one help me on this?

推荐答案

需要注意的是一个静态的结构本身是从结构的静态成员不同。虽然你可以声明静态结构变量：

Note that a static struct itself is different from a static member of a struct. While you can declare a static struct variable:

static struct MyStruct s;

您不能用静态成员定义一个结构类型：

you can't define a struct type with a static member:

struct MyStruct {
    static int i; // <- compiler error
};

这样做的原因是，在C，一个结构是一类 - （。即​​静态）声明一个类型，它的成员变量始终是相同的实例该类型的多个实例简直是痴人说梦。在C ++中，结构是现实类（它们只在成员的默认可见范围不同），以及C ++中的static关键字意味着在这种情况下别的东西。这意味着一个类的方法 - 但由于C没有类和方法，这是没有意义的，是无效的用C

The reason for this is that in C, a struct is a type - declaring a type of which a member variable is always the same instance (i. e. static) for multiple instances of that type is simply nonsense. In C++, structs are in reality classes (they only differ in the default visibility scope of members), and in C++ the static keyword means something else in this case. It means a class method - but since C doesn't have classes and methods, this doesn't make sense and is invalid in C.

经验教训：C ++不是C

Lesson learned: C++ is not C.

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