这是第一个＆QUOT的目的;节点＆QUOT;在声明：QUOT; typedef结构节点{ - - - }节点;＆QUOT;？ [英] What is the purpose of the first "node" in the declaration: "typedef struct node { - - - } Node;"?

问题描述

我要成为与链接的数据结构更好地了解学习code例子从我的教授。

I am studying code examples from my professor in order to become better acquainted with linked data structures.

在我们的链接list.c例如教授定义了一个类型节点如下：

In our linked-list.c example the professor defines a type Node as follows:

typedef struct node {
  int data;
  struct node *next;
} Node;

什么是小写的节点的点？我是IM pression，你可以只写下，例如：

What's the point of the lower case node? I was under the impression that you could just write, for example:

typedef struct {
  int data;
  struct node *next;
} Node;

和然后使用节点作为其自己的类型。是否有事可做的事实，如果不包含那么当编译器正在评估code就不能明白什么叫结构节点*下一个较低的情况下，节点？

and then use Node as its own type. Does it have something to do with the fact that if you don't include a lower case node then when the compiler is evaluating the code it will not be able to understand what is meant by "struct node *next"?

推荐答案

在此声明，请看下图：

struct node {
  int data;
  struct node *next;
};

typedef struct node Node;

这可以组合成一个单独的语句（简化报关）：

This can be combined into a single statement (simplifying a declaration):

typedef struct node {
  int data;
  struct node *next;
} Node;

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