从GATE纸C程序 [英] A c program from GATE paper

问题描述

嘿昨天我已经给我的门考试，这次考试有一个问题：

Hey all yesterday i have given my GATE exam and in this exam there was a question:

什么C程序打印下列片​​段？

char c [] = "GATE2011";
char *p =c;
printf ( "%s", p+p [3] − p [1]) ;

选项：

(A) GATE2011
(B) E2011
(C) 2011
(D) 011

答案是 C 。当我试图在我的电脑但如何在code？

Answer is 'C'. when i tried the code on my computer But how??

在此先感谢

推荐答案

这是指针运算：

char c [] = "GATE2011";
// indices:  01234567
char *p =c;

P [1] 是 A 字符code， P [3 ] 是电子字符code，它们的区别（电子 code减去 A code）为4，那么这种差别将被添加到 p 指针，你有 2011 地址子传递到的printf（）。

p[1] is A character code, p[3] is E character code, their difference (E code minus A code) is 4, that difference is then added to p pointer and you've got the address of 2011 substring passed into printf().

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