如何通过用户定义的宏x codebuild？ [英] how to pass the user-defined macro to xcodebuild?

问题描述

我建立在命令行x codebuild我的项目。不是X中code。我想一些果渣传递给项目，以便它可以影响code。如低于code：

I build my project by xcodebuild in command line. Not in xCode. I want to pass some marc to the project so that it can affect the code. Such as code below:

#if (API_TYPE == 1)
  #define URL_API @"https://dapi.xxx.com/1.1/"
#elif (API_TYPE == 2)
  #define URL_API @"https://tapi.xxx.com/1.1/"
#elif (API_TYPE == 3)
  #define URL_API @"https://api.xxx.com/1.1/"
#else
  #error "API_TYPE value error! should be only value 1,2,3 !"
#endif 

我想通过code文件外的定义API_TYPE的。如通过X codebuild命令。
但它不喜欢这个工作：

I want pass the define of API_TYPE outside the code files. Such as through xcodebuild command. But It doesn't work like this:

xcodebuild -sdk xxx -target xxx SYMROOT=${XCSYMROOT} API_TYPE=${APITYPE}

的API_TYPE的值没有改变。但SYMROOT的价值发生了变化。
那么，如何可以实施传递值外API_TYPE？

The API_TYPE's value was not changed. But the SYMROOT's value was changed. So how can I implement that passing the value to API_TYPE outside ?

推荐答案

我知道这是一个古老的职位，但为什么不使用：

I know this is an old post, but why not just use:

xcodebuild GCC_PREPROCESSOR_DEFINITIONS='$GCC_PREPROCESSOR_DEFINITIONS API_TYPE=1'

如果您希望能够拥有它选择覆盖现有的应用程序定义，只是code是这样的：

If you want to be able to have it optionally override an existing define in app, just code something like this:

#define DEFAULT_API_TYPE 1

#ifdef API_TYPE
  #define REAL_API_TYPE API_TYPE
#else
  #define REAL_API_TYPE DEFAULT_API_TYPE
#endif

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