如何使用数组索引作为一个经营者？ [英] How to use an array index as an operator?

问题描述

如何使用数组索引作为一个经营者？

How to use an array index as an operator?

使得：

#include<stdio.h>

main()
{
    char sign[]={'+','-'};
    int a, b;
    a = 12 sign[1] 10;
    printf("%d",a);
}

其实这code不起作用。什么将是正确的code为这种类型的节目？

Actually this code doesn't work. What will be the right code for this type of programs?

推荐答案

最简单的就是使用switch语句或的if-else链。

The simplest is to use a switch statement or if-else chain.

#include<stdio.h>

int main() {
    char sign[]={'+','-'};
    int a,b;

    switch (sign[1]) {
        case '+':
            a = 12 + 10;
            break;

        case '-':
            a = 12 - 10;
            break;
    }

    printf("%d",a);
}

如果我这样做，我可能最终会移动一些逻辑成一个函数虽然。也许是这样的：

If I was doing this, I'd probably end up moving some of the logic into a function though. Perhaps something like this:

#include<stdio.h>

int perform_operation(char op, int lhs, int rhs) {
    switch (op) {
        case '+':
            return lhs + rhs;

        case '-':
            return lhs - rhs;

        default:
            return 0;
    }
}

int main() {
    char sign[]={'+','-'};
    int a = perform_operation(sign[1], 12, 10);
    printf("%d",a);
}

这篇关于如何使用数组索引作为一个经营者？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！