混淆输出 [英] Confusion about the output

问题描述

#include<stdio.h>
int main(void)
{
    int i=1,j=-1;
    if((printf("%d",i))<(printf("%d",j)))
        printf("%d",i);
    else 
        printf("%d",j);
    return 0;
}

由于的printf（）返回成功打印的字符数，病情将如果（1。1）这是假的，但执行if部分和输出 1-11 。为什么会这样？

As printf() returns the number of characters successfully printed, the condition will be if(1<1) which is false but the if part is executed and the output is 1 -1 1. Why this is happening?

推荐答案

我认为这是相当明显的：'1'是一个字符，-1为二。一个是小于2。

I think it is rather obvious: '1' is one character, '-1' is two. One is less than two.

这篇关于混淆输出的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！