调试code用C [英] Debugging code in C

问题描述

有人能告诉我什么是错我的code和为什么它是产生此输出。

code：

  INT的main（）{
  无符号NUM;
  焦炭反应;做{
 的printf（请输入一个正整数大于1且小于2000：）;
 scanf函数（％D，试验＃）;
 如果（NUM→1＆放大器;试验＃＆下; 2000）{
    的printf（所有％D的主要因素，下面给出：\\ n，NUM）;
    printPrimeFactors（NUM）;
    的printf（\\ n \\ n此％d个鲜明的首要因素，下面给出：\\ n，NUM）;
    printDistinctPrimeFactors（NUM）;
 }
 其他{
    的printf（\\ nSorry这个数字不1和2000年\\ n之间落）;
 }
 的printf（\\ n \\ n您想尝试另一个号码说Y（ES）或N（O）：）;
 的getchar（）;
 响应=的getchar（）;
}
而（响应=='Y'||响应=='Y'）; //如果响应是Y或y，则程序再次运行
输出（感谢您使用我的节目再见\\ n \\ n！）; //如果不是Y或Y，程序终止
返回0;
}
 

输出：

 请输入一个正整数大于1并且小于2000时：1600
所有的1600的素因数给出如下：
2 2 2 2 2 2 5 51600独特的首要因素，给出如下：
2 5你想尝试另一个号码？说Y（ES）或N（O）：是
请输入大于1比2000的一个正整数，更大的少：所有1600的主要因素，给出如下：
2 2 2 2 2 2 5 51600独特的首要因素，给出如下：
2 5你想尝试另一个号码？说Y（ES）或N（O）：感谢您使用我的程序。再见！
 

解决方案

在问你是否要重复，你只读过是，留下 ES 在标准输入排队。当你去阅读下一个数字， scanf函数试图解析为一个数字，失败，并返回不改变 NUM 。当您提示用户，你需要刻录全线飘红。

Can someone tell me what is wrong with my code and why it is producing this output.

Code:

int main(){
  unsigned num;
  char response;

do{
 printf("Please enter a positive integer greater than 1 and less than 2000: ");
 scanf("%d", &num);
 if (num > 1 && num < 2000){
    printf("All the prime factors of %d are given below: \n", num);
    printPrimeFactors(num);
    printf("\n\nThe distinct prime factors of %d are given below: \n", num);
    printDistinctPrimeFactors(num);
 }
 else{
    printf("\nSorry that number does not fall between 1 and 2000.\n");
 }
 printf("\n\nDo you want to try another number? Say Y(es) or N(o): ");
 getchar();
 response = getchar();
}
while(response == 'Y' || response == 'y'); // if response is Y or y then program runs again
printf("Thank you for using my program. Good Bye!\n\n"); //if not Y or y, program terminates
return 0;
}

Output:

Please enter a positive integer greater than 1 and less than 2000: 1600
All the prime factors of 1600 are given below: 
2 2 2 2 2 2 5 5 

The distinct prime factors of 1600 are given below: 
2 5 

Do you want to try another number? Say Y(es) or N(o): yes
Please enter a positive integer greater than 1 and less than 2000: All the prime factors of 1600 are given below: 
2 2 2 2 2 2 5 5 

The distinct prime factors of 1600 are given below: 
2 5 

Do you want to try another number? Say Y(es) or N(o): Thank you for using my program. Good     Bye!

解决方案

When you ask whether you want to repeat, you only read the y, leaving the es queued up in stdin. When you go to read the next number, scanf tries to parse that as a number, fails, and returns without altering num. When you prompt the user, you need to burn that whole line.

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