如何使用精灵作为另一个精灵锚点？ [英] how to use a sprite as an anchor point of another sprite?

问题描述

我想知道，如果你可以，连接两个精灵在libgdx。

I want to know , if you can , join two sprites in libgdx .

让我解释一下，我有一个飞船，我必须把我的游戏...而且是第一个精灵。

Let me explain, I have a spaceship that I have to turn in my game ... and is the first sprite .

另一个精灵我会把飞船上的提示，这样，当它变成我，我通过第二雪碧我总是可以知道的坐标，因此得出一个载体​​，以推进我的船。

another sprite I would put on the tip of the spacecraft so that when it turns me I through the second sprite I can always know the coordinates and so derive a vector in order to advance my ship .

我是新来的libgdx，如果任何人有任何想法将不胜感激。

I'm new to libgdx and if anyone had any idea would be grateful.

感谢你。

修改 ：我会按照它总是使其他精灵的位置，目前还没有发生，提示吗？谢谢你。

EDIT : I would follow that always render the position of the other sprites , currently does not happen , tips ? Thank You.

@Override
public void render () {

    sprite.setPosition(Gdx.graphics.getWidth() / 2 - sprite.getWidth()/2, Gdx.graphics.getHeight() / 2 - sprite.getHeight()/2);
    point.setPosition(sprite.getX() + (sprite.getWidth()/2 - point.getWidth()/2), sprite.getY() + (sprite.getHeight() / 2 + point.getHeight()));

    Gdx.gl.glClearColor(1, 1, 1, 1);
    Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);

    if(Gdx.input.isButtonPressed(Input.Buttons.LEFT)){
        //sprite.setPosition(Gdx.input.getX() - sprite.getWidth()/2, Gdx.graphics.getHeight() - Gdx.input.getY() - sprite.getHeight()/2);
        if(Gdx.input.getX() < Gdx.graphics.getWidth() / 2)
        {
            //System.out.println("x: " + Gdx.input.getX() + " - y: " + Gdx.input.getY());
            sprite.setRotation(rotation++);
        }
        else
        {
            System.out.println("x: " + Gdx.input.getX() + " - y: " + Gdx.input.getY());
            sprite.setRotation(rotation--);
            point.setRotation(rotation--);
        }
    }

    batch.begin();
    spacesprite.draw(batch);
    sprite.draw(batch);
    point.draw(batch);
    batch.end();
}

编辑2

正如你可以在图片中看到，我想，当我旋转飞船的精灵，红点（这是另一种精灵）留在飞船的一角。所以，你可以计算出与两个精灵的起源点的载体。

As you can see in the picture , I would like that when I rotate the sprite of the spacecraft , the red dot ( which is another sprite ) remain on the tip of the spacecraft . So you can calculate a vector with the points of origin of the two sprites .

我希望已经明确。 两个精灵联合是不可能在libgdx别的吗？

I hope to have been clear . A union of two sprites is not possible in libgdx else?

修改3

照片，我希望永远当船旋转红球留在飞船的一角。这可能吗？

picture , I wish that when the ship rotates the red ball remains always on the tip of the spacecraft . is it possible?

推荐答案

如果你的两个精灵具有相同的宽度可以使用这样的：

If your two sprite have the same width can use this:

这是psudo code铁道部或更少。

this is psudo code mor or less.

float pointY = yourSprite.getY() + yourSprite.getHeight();
float pointX = yourSprite.getX(); 

yourOtherSprite. setX(pointX);
yourOtherSprite. setY(pointY);

如果diferente宽度

if diferente width

float pointY = yourSprite.getY() + yourSprite.getHeight();
float pointX = yourSprite.getX() + (yourSprite.getWidth() / 2); 

yourOtherSprite. setX(pointX - (thisSprite.getWidth() / 2));
yourOtherSprite. setY(pointY);

我现在不能测试，但让你有一个想法。

I can not test now, but so you have an idea.

新

我不知道这是你的意思，如果不是这样评论，并删除：

I do not know if is this what you mean if not so comment it and delete:

P.S：点*是一个Vector2：

P.s: points* is a Vector2:

pointSpriteA.x = yourSprite.getX() + (yourSprite.getHeight() / 2);
pointSpriteB.x = yourOtherSprite.getY() + (yourOtherSprite.getHeight() / 2);

pointSpriteA.y = yourSprite.getY() + (yourSprite.getWidth() / 2);
pointSpriteB.y = yourOtherSprite.getY() + (yourOtherSprite.getWidth() / 2);

pointC.X = (pointSpriteA.x + pointSpriteB.x) / 2);
pointC.y = (pointSpriteA.Y + pointSpriteB.y) / 2);

的pointC向量是两个向量的中心。

the pointC vector is the center of the two vectors.

如果这就是你想要什么，并问自己，怎么转？精灵可这有助于。

if that's what you want, and ask yourself, how to rotate? sprites can this helps.

<一个href="http://stackoverflow.com/questions/27555023/libgdx-rotate-a-2d-array-of-sprites-around-their-center/27555676#27555676">LibGDX - 绕其中心精灵的二维数组

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