跳过用C scanf函数声明 [英] Skipping over Scanf statement in C

问题描述

我写的刽子手客观的C程序。我需要复制已经给我另一个程序。我已经做了大部分，但我有一个问题。它具有精确复制其他程序，所以我走进了另一个和输入的字符到字长。它想出了数必须介于3至14（含）语句，并要求我再输入一个数字，但它开始无限循环。它的工作原理，当我进入低于3一个数字，大于14（出现的错误，并请求另一个输入），但以字母它无限循环。有任何想法吗？？？
谢谢

 同时（我== 0）{            的printf（\\ n \\ n＆gt;请输入字长：）;
                scanf函数（％i的，＆安培;字长）;
            的printf（\\ n \\ n）;
            如果（数→3＆放大器;＆放大器;数＆下; 14）{
                继续;
            }
            其他的printf（数必须是3至14（含）之间的）;
            }
 

解决方案

您正在检查数量，但似乎你必须检查字长变量，（如@Narkha指出的）使用破而不是继续从循环退出

I am writing an objective c program for hangman. I need to replicate another program which has been given to me. I have done most of it, but am having an issue. It has to replicate the other program exactly, so I went into the other one and entered a character into the wordlength. It came up with the "number must be between 3 and 14 (inclusive)" statement, and asked me to enter a number again, but it started to loop infinitely. It works when i enter a number lower than 3 and larger than 14 (comes up with the error and asks for another input) but with a letter it infinitely loops. Any ideas??? Thanks

while (i == 0){

            printf("\n\n > Please enter a word length: ");
                scanf("%i", &wordLength);
            printf("\n\n");
            if (number > 3 && number < 14) {
                continue;
            }
            else printf("number must be between 3 and 14 (inclusive)");
            }

解决方案

You are checking number but seems that you must check wordLength variable, and (as pointed out by @Narkha) use break instead of continue to exit from loop.

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