如何将链路本地地址绑定到IPv6套接字 [英] how to bind a link local address to an ipv6 socket

问题描述

这个问题可以被视为一姐的问题，<一个href=\"http://stackoverflow.com/questions/2455762/why-cant-i-bind-ipv6-socket-to-a-linklocal-address\">$p$pvious 之一张贴自己。这是非常繁琐的，当你想要一个链路本地地址绑定到IPv6套接字，你需要设置体sockaddr_in6 sin6_scope_id 字段code>结构。我想知道，如果有人能提供以下建议的解决方案。

This question can be treated as a sister question of previous one posted by myself. It is very tedious that when you want to bind a link local address to an IPv6 socket, you need to set the sin6_scope_id field of the sockaddr_in6 struct. I'm wondering if someone can provide a solution following good practice.

推荐答案

的IPv6链路本地地址不在节点上独一无二的，这只是为NIC独特这就是为什么你必须指定范围-ID。换句话说，它是完全有效的多个适配器使用完全相同的IPv6地址。

The IPv6 link-local address is not unique on the node it's only unique for the NIC which is why you have to specify the scope-id. In other words it is perfectly valid to have multiple adapters with exactly the same IPv6 address.

这意味着你应该在输入范围-ID或合适的文本形式（％为eth0，％1），您可以传递给的getaddrinfo（）。

This means you should take in as input the scope-id or suitable text form (%eth0, %1) that you can pass to getaddrinfo().

一个方法是采取一个IPv6链路本地地址，枚举接口，如果只有一个匹配使用，如果超过一个匹配，那么救助与接口列表，并获得用户指定哪一个在全形式。

One method is to take in a IPv6 link-local address, enumerate the interfaces and if only one matches use that, if more than one match then bail out with a list of interfaces and get the user to specify which one in full form.

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