是什么typedef结构节点* NODE说明什么？ [英] what does typedef struct node *NODE indicate?

问题描述

 结构节点
{
    INT系数;    INT EXP;    结构节点*链接;
};typedef结构节点*节点;
 

解决方案

它定义节点作为类型结构节点的代名词* ，所以当你将声明类型的变量节点你会实际上宣告一个指向结构节点。

就个人而言，我不认为这样的声明是一个好主意：你隐藏指针（这是几乎总是一个坏主意），而且，你不强调这个事实以任何方式进入新的名称。

struct node
{
    int coef;

    int exp;

    struct node *link;
};

typedef struct node *NODE;

解决方案

It defines NODE as a synonym for the type struct node *, so when you'll be declaring a variable of type NODE you'll be actually declaring a pointer to struct node.

Personally, I don't think that such declaration is a good idea: you're "hiding a pointer" (which is almost always a bad idea), and, moreover, you are not highlighting this fact in any way into the new name.

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