红宝石传递数组值成C数组 [英] Passing ruby array values into a C array
问题描述
我试图让在C红宝石独立FFT扩展的基础上的这个配方
I'm trying to make a standalone FFT extension for ruby in C, based on this recipe
我已经注意到通过红宝石和C之间的不同值的几种方法。但是即时通讯相当新的Ruby和C和不能工作如何从一个值Ruby对象数组复制到C数组。
I've noted several methods for passing different values between ruby and c. However im fairly new to both ruby and C and can't work out how to copy an array from a VALUE ruby object into a C array.
编译错误:
SimpleFFT.c:47:错误:下标值既不是数组,也不指针
The compilation error: SimpleFFT.c:47: error: subscripted value is neither array nor pointer
而code:
#include "ruby.h"
#include "fft.c" // the c file I wish to wrap in ruby
VALUE SimpleFFT = Qnil;
void Init_simplefft();
VALUE method_rfft(VALUE self, VALUE anObject);
void Init_simplefft() {
SimpleFFT = rb_define_module("SimpleFFT");
rb_define_method(SimpleFFT, "rfft", method_rfft, 1);
}
VALUE method_rfft(VALUE self, VALUE inputArr) {
int N = RARRAY_LEN(inputArr); // this works :)
// the FFT function takes an array of real and imaginary paired values
double (*x)[2] = malloc(2 * N * sizeof(double));
// and requires as an argument another such array (empty) for the transformed output
double (*X)[2] = malloc(2 * N * sizeof(double));
for(i=0; i<N; i++) {
x[i][0]=NUM2DBL(inputArr[i]); // ***THIS LINE CAUSES THE ERROR***
x[i][1]=0; // setting all the imaginary values to zero for simplicity
}
fft(N, x, X); // the target function call
// this bit should work in principle, dunno if it's optimal
VALUE outputArr = rb_ary_new();
for(i=0; i<N; i++){
rb_ary_push(outputArr, DBL2NUM(X[i][0]));
}
free(x);
free(X);
return outputArr;
}
在此先感谢:)
推荐答案
您不能下标 inputArr
,因为它是一个值
而不是C数组。也就是说,这是一个标量类型。要访问一个特定的索引,使用
You can't subscript inputArr
because it's a VALUE
rather than a C array. Ie, it's a scalar type. To access a particular index, use
rb_ary_entry(inputArr, i)
顺便说一句,你可能想先验证它是一个数组:
As an aside, you might want to verify first that it's an array:
Check_Type(rarray, T_ARRAY);
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