整洁的方式来处理错误的malloc如果没有了NULL每一个malloc调用后，被送回检查？ [英] Neat way to handle malloc error without checking if NULL has been returned after every single malloc call?

问题描述

在我的code几乎每一个功能都有一个或多个的malloc电话，每一次我必须做的是这样的：

In my code almost every function has one or more malloc calls, and each time I have to do something like:

char *ptr = (char *)malloc(sizeof(char) * some_int);
if (ptr == NULL) {
    fprintf(stderr, "failed to allocate memory.\n");
    return -1;
}

这是code的四个额外的行，如果我加入他们每次之后我用一个malloc，我的code的长度将增加很多..所以有一种优雅的方式来处理这个？

that's four extra lines of code and if I add them everytime after I use a malloc, the length of my code will increase a lot.. so is there an elegant way to deal with this?

感谢你了！

推荐答案

很抱歉，但没有什么可以做，在C.除... 喘气......把它包在所有宏这将自动化如果检查，并允许您编写自定义的错误处理$ C $每次℃。在那里，我说。

Sorry, but there's nothing you can do about that in C. Except... gasp... wrap it all in a macro which will automate the if check and allow you to write custom error-handling code each time. There, I said it.

说真的，并不意味着C到提供这样的便利。如果你不介意当场退出程序，可以在过程中，做退出当分配失败的函数包裹它 - 但是这没有通用的解决方案。

Seriously, C isn't meant to provide conveniences like this. If you don't mind exiting the program on the spot, you can wrap it in a function of course that does exit when the allocation fails -- but that's no general solution.

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