快速的输入输出功能 [英] Fast input output function

问题描述

#define getcx getchar_unlocked
inline void inp( int &n )//fast input function
{
   n=0;
   int ch=getcx();int sign=1;
   while( ch < '0' || ch > '9' ){if(ch=='-')sign=-1; ch=getcx();}

   while(  ch >= '0' && ch <= '9' )
           n = (n<<3)+(n<<1) + ch-'0', ch=getcx();
   n=n*sign;
}

您好我一直在使用输入上述功能在不同的编码比赛，但为什么它快速始终无法理解。我所知道的逻辑，但不知道它的牢度的概念。例如这是什么线做getchar_unlocked的#define getcx。此外，我不知道任何快速输出功能，因此没有任何快速输出功能还可

Hi I have been using the above function for input in various coding contests but was never able to understand why is it fast. I know the logic but don't know the concept of it's fastness. For example what is this line doing "#define getcx getchar_unlocked" . Also I don't know any fast output function so is there any fast output function also

推荐答案

的的#define 使用preprocessor使 getcx 是一个短手功能 getchar_unlocked（）< /一> ，这是一种非锁定字符阅读功能

The #define uses the preprocessor to make getcx be a short-hand for the function getchar_unlocked(), which is a non-locking character-reading function.

这是一个有点真棒，你已经在多个编码竞赛竞争不理解这个pretty基础件C的。

It's a bit awesome that you've competed in several coding contests without understanding this pretty basic piece of C.

该手册页我联系上面提到 putc_unlocked（）这听起来像pretty同样的事情，但输出。

The manual page I linked to above mentions putc_unlocked() which sounds like pretty much the same thing but for output.

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