用C定义操作precedence [英] Operator precedence in C Definitions

问题描述

维基百科声称， [] 运算符precedes的 * 在评价经营者。

Wikipedia claims that the [] operator precedes the * operator in evaluation.

那么，为什么下面的语句：

Then, why does the following statement:

char *a[3];

申报的3字符指针数组，而不是一个指针的3个字符数组按照操作precedence？

declare an array of 3 character pointers, rather than a pointer to an array of 3 characters as per the operator precedence?

推荐答案

由于，如维基百科说， [] 具有较高的precedence比 * ？

Because, as Wikipedia says, [] has higher precedence than *?

处理的声明中， A [3] 被处理为3阵'你处理之前， * 。

Processing the declaration, the a[3] is processed as 'array of 3' before you process the *.

要声明一个指向三个字符数组，你必须用括号覆盖默认的precedence：

To declare a pointer to an array of three characters, you have to use parentheses to override the default precedence:

char (*a)[3];

现在括号采取阵列上precedence。

Now the parentheses take precedence over the array.

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