在一个阵列指向获取其所有内容 [英] Pointing at an array to get all its contents

问题描述

因此​​，阵列指向他们的第一个元素。

So, arrays are pointers to their first element.

浮色[4] = {rColor，gColor，bColor，阿尔法};

因此​​，只是普通的颜色点＆放大器;颜色[0] ;

Thus, just plain color points to &color[0];

现在假设我有一个正是如此结构：

Now suppose I have a struct thusly:

struct Colors{
float color[4];
};

现在我发现我能做到这一点相当精致：

Now I have found I can do this quite fine:

Colors myColor={{*color}};

我也可能只是这样做：

I could also just do this:

Colors myColor={{color[0]}};

我只是指着一个元素，但结构预计4，所以它一直在寻找过去的这个元素。

I am only pointing at one element, but the struct expects 4, so it keeps looking past this element.

首先，我要检查是细做，法律和好。显然，如果你正在传递一个大阵，这是语法和打字挺方便的。

First, I want to check that is fine to do, legal and okay. Obviously if you are passing a large array, this is quite convenient on the syntax and typing.

第二，我想验证为什么这个作品的理由。由于颜色孤单是一个指针， * 是一个间接运算符的检索指向的内存，因此，数组。所以基本上我们只需调用与间接指针得到整个数组。是否正确？

Second, I want to verify the reasoning about why this works. Since color alone is a pointer, the * is an indirection operator that retrieves the memory pointed to, thus, the array. So essentially we get the entire array by just calling its pointer with indirection. Correct?

推荐答案

的结构，联合Intializers和数组有，是根据它省略元素与 0 。

Intializers of structures, unions and arrays have the particular property that elements that are omitted from it are initialized with 0.

要初始化的整体结构，你的颜色您也可以使用相同类型的其他对象。

To initialize a whole structure as your Colors you can also use any other object of that same type.

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