为什么＆QUOT;＆的fopen QUOT;功能不使用枚举？ [英] Why "fopen" function does not use enumerations?

问题描述

什么是使用的原因为const char * 像这样选择开放模式，而不是一个枚举的

What is the reason to use a const char* for selecting the open mode instead of an enum like this:

enum open_mode {
        READ,
        READ_BINARY,
        WRITE,
        ...
};

这不会是更简单地用一个枚举？

It wouldn't be more simply to use an enum?

推荐答案

原因是最有可能的历史：功能的fopen 一直围绕在前期K＆安培;中的R版本的语言，而枚举已被添加到该语言只为ANSI标准

The reason is most likely historical: function fopen has been around in the early K&R version of the language, while enum has been added to the language only for the ANSI standard.

的时候，加入枚举 S中的语言一直在这样wides $ P $垫使用，改变等重要功能的签名是不切实际的。

By the time enums were added the language has been in such widespread use that changing the signature of such important function was impractical.

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