与指针为const char C的误差[] [英] C error with pointer and const char[]

问题描述

我有一个const char ARR []参数，我想遍历，

I have a const char arr[] parameter that I am trying to iterate over,

char *ptr;
for (ptr= arr; *ptr!= '\0'; ptr++) 
  /* some code*/

我得到一个错误：赋值丢弃了指针目标类型的限定

I get an error: assignment discards qualifiers from pointer target type

现为const char []的处理不同于非const？

Are const char [] handled differently than non-const?

推荐答案

开关* PTR的声明是

Switch the declaration of *ptr to be.

const char* ptr;

问题是，你基本上是指定一个const char *为char *。这是常量的侵犯，因为你从一个const去一个非const。

The problem is you are essentially assigning a const char* to a char*. This is a violation of const since you're going from a const to a non-const.

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