在C位，我怎么访问底层位在C浮动？ [英] Bits in C, how do I access the underlying bits in a C float?

问题描述

给定两个浮点数A和B，这是命令行参数，我必须创建方法来做他们按位运算。包括与，或，非，异或，浮点除等等...

Given a two floating point Numbers A and B, which are command line arguments, I must create methods to do bitwise operations on them. Including And, Or, Not, xOr, floating Point addition etc...

我如何可以访问每一位使用C？我需要访问特定的1和0。任何想法如何？

How can I access each bit in C? I need to access the specific 1's and 0's. Any idea how?

推荐答案

下面是使用工会的例子，如基思建议。

Here's an example using unions, as Keith suggests.

/* -std=c99 */
#include <stdio.h>

int main(int argc, char * argv[]) {

  /* note, I'm assuming an int has the same size of a float here */
  assert( sizeof(unsigned int) == sizeof(float) );

  union {
    float floating;
    unsigned int integer;
  } a;

  a.floating = 3.14;

  /* prints the bits in reverse order */
  unsigned int temp = a.integer;
  for( int i = 0; i < sizeof(float)*8; i++ ) {
    printf("%d", temp & 0x1);
    temp = temp >> 1;
  }
}

编辑：改签署整数为无符号。

changed signed ints to unsigned.

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