如何启动一个进程并等待它的子进程结束 [英] How to start a process and wait for its child process to finish

问题描述

有一个启动一个进程，并等待它的子进程结束的方式？我的问题如下。我有一个setup.exe文件。如果我启动它，它运行4-5秒，并启动1或2新工艺，运行setup.exe关闭。

Is there a way to start a process, and wait for its child process to finish? My problem is the following. I have a setup.exe. If i start it, it runs for 4-5 secs and starts 1 or 2 new processes, and the setup.exe closes.

如果我的CreateProcess和WaitForSingleObject的开始SETUP.EXE，然后它会等待才把直到setup.exed关闭。

If i start setup.exe with createprocess and with WaitForSingleObject, then it will wait only then until the setup.exed closes.

有没有一种方法，要等到新工艺，由开始的setup.exe完呢？

Is there a way, to wait until the new processes, started by setup.exe finishes too?

感谢

推荐答案

莫比，您可以创建在启动一个互斥体并锁定。然后，使基地过程中使用WaitForSingleObject的API等待。当它的主人进程终止互斥自动销毁。

Maby you can create a Mutex on startup and lock it. Then, make base process wait for it using WaitForSingleObject api. The Mutex is automatically destroyed when its owner process is terminated.

另外，您可以创建用于终止当过程结束后子进程一个tmp文件，您可以SETUP.EXE检查是否存在FRIM知道如果进程仍在运行。

Alternatively you can create a tmp File in the child process which you terminate when the process is finished, your setup.exe can check if the frim exists to know if the process is still running.

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