指针和字符串分割造成的故障 [英] Pointers and Strings causing segmentation fault

问题描述

  

可能重复：结果
  <一href=\"http://stackoverflow.com/questions/9460260/what-is-the-difference-between-char-a-string-and-char-p-string\">What为char之间的差的[] =＆ldquo;串rdquo ;;和char * p =＆ldquo;串rdquo ;;

 的char *海峡=你好;
的printf（％C，++ * STR）;
 

这给出了与海湾合作委员会的Linux分段错误。
当下的第一个语句修改为

 字符海峡[10] =你好;
 

它的工作原理。可能是什么原因呢？

解决方案

这是不确定的行为试图修改字符串。

编译器可以自由地将其放置在只读存储器（因为它可能是你的情况一样）。试图修改只读存储器是什么可能触发段错误。

Possible Duplicate:
What is the difference between char a[] = “string”; and char *p = “string”;

char *str = "Hello";
printf("%c",++*str);

This gives segmentation fault on linux with gcc. The moment the first statement is changes to as

char str[10] = "Hello";

It works. What may be the reason?

解决方案

It is undefined behaviour to attempt to modify a string literal.

The compiler is free to place it in read-only memory (as it probably does in your case). Attempting to modify read-only memory is what's probably triggering the segfault.

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