伯爵用C行数，字数和字符 [英] Count lines, words and characters in C

问题描述

下面是我的函数计算的行数，字数和字符数 -

Below is my function to count number of lines, words and characters -

void count(char* file) {

int fd;
long end=0;
char c;
long words=0;
long lines=0;

if((fd=open(file, O_RDONLY))>0){
    end=lseek(fd, 0, SEEK_END);
    lseek(fd, 0, SEEK_SET);
    while(read(fd, &c, 1)==1){
        if(c == ' ')
            words++;
        if(c == '\n') {
            lines++;
            words++;
        }
    }

    printf("The Number of characters in file is: %ld\n",end);   
    printf("The Number of lines in file is: %ld\n",lines);
    printf("The Number of words in file is: %ld\n",words);

    close(fd);
}
else{
    printf("Error: ",strerror(errno));
}
}

我得到正确的线条和文字的数量，但错了的字数。正如你看到的我指望的空格数，如果有多个空格，怎么算的话（我不想使用f *功能，就像文件指针的fscanf）？如何wc命令处理呢？

I am getting right on number of lines and characters, but wrong on number of words. As you see i am counting number of spaces, if there are multiple spaces, how to count words(I don't want to use f* functions, like fscanf with filepointer) ? How does wc command handle this ?

推荐答案

你为什么不使用 strpbrk（）标准libc中的功能？做一些事情ALSE：

why you don't use strpbrk() standard libc function? Do some thing alse:

    char keys[] = " \n";
    ...
    while( expression ){

        ret = read(fd, buf, BUF_LEN - 1);

        if (ret == -1)
            /*do errno*/
        else if ( ret ) {

            char* p = buf;
            buf[ ret ] = '\0';

            while( (p = strpbrk(p, keys)) ) {
                if (*p == key[1])
                    ++lines;
                ++words;
                ++p;
            }
        }
        else
            /* do close file */
    }

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