接口定义构造函数签名？ [英] Interface defining a constructor signature?

问题描述

这很奇怪，这是我第一次碰到这个问题，但是：

It's weird that this is the first time I've bumped into this problem, but:

你如何在C＃中的接口定义构造函数？

How do you define a constructor in a C# interface?

修改结果
有些人希望有一个例子（这是一个自由时间的项目，所以是的，这是一场游戏）

Edit
Some people wanted an example (it's a free time project, so yes, it's a game)

IDrawable结果
 +更新结果
 +绘制

IDrawable
+Update
+Draw

要能够更新（检查屏幕等边），并绘制它本身总是需要一个 GraphicsDeviceManager 。所以我想确保对象有对它的引用。这属于在构造函数中。

To be able to Update (check for edge of screen etc) and draw itself it will always need a GraphicsDeviceManager. So I want to make sure the object has a reference to it. This would belong in the constructor.

现在，我写下来我觉得我实施这里是的IObservable 和 GraphicsDeviceManager 应采取在 IDrawable ...
这似乎不是我不明白的XNA框架或框架不是想出来的非常好。

Now that I wrote this down I think what I'm implementing here is IObservable and the GraphicsDeviceManager should take the IDrawable... It seems either I don't get the XNA framework, or the framework is not thought out very well.

修改结果
似乎有大约在接口方面，我国的构造函数的定义有些混乱。接口可以确实无法实例因此不需要构造。我想确定是构造一个签名。酷似一个接口可以定义一个特定方法的签名，该接口可以定义构造函数的签名。

Edit
There seems to be some confusion about my definition of constructor in the context of an interface. An interface can indeed not be instantiated so doesn't need a constructor. What I wanted to define was a signature to a constructor. Exactly like an interface can define a signature of a certain method, the interface could define the signature of a constructor.

推荐答案

您不能。这是偶尔的痛苦，但你不能用正常的方法反正调用它。

You can't. It's occasionally a pain, but you wouldn't be able to call it using normal techniques anyway.

在一篇博客文章中，我建议<一href=\"http://$c$cblog.jonskeet.uk/2008/08/29/lessons-learned-from-protocol-buffers-part-4-static-interfaces/\">static接口这将只可用在泛型类型的限制 - 但可能是非常方便的，IMO

In a blog post I've suggested static interfaces which would only be usable in generic type constraints - but could be really handy, IMO.

有关，如果你的可能的定义一个接口中的一个构造函数，你会遇到麻烦派生类的一点：

One point about if you could define a constructor within an interface, you'd have trouble deriving classes:

public class Foo : IParameterlessConstructor
{
    public Foo() // As per the interface
    {
    }
}

public class Bar : Foo
{
    // Yikes! We now don't have a parameterless constructor...
    public Bar(int x)
    {
    }
}

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