C＃中：等待所有线程完成 [英] C#: Waiting for all threads to complete

问题描述

我运行到了code，我正在写，我需要等待所有的线程组中来完成，一个超时的通用模式。超时应该是需要时间的所有的线程来完成，因此简单地做的Thread.join（超时）为每个线程将无法正常工作，因为可能超时，然后是超时* numThreads。

I'm running into a common pattern in the code that I'm writing, where I need to wait for all threads in a group to complete, with a timeout. The timeout is supposed to be the time required for all threads to complete, so simply doing thread.Join(timeout) for each thread won't work, since the possible timeout is then timeout * numThreads.

现在我做类似以下内容：

Right now I do something like the following:

var threadFinishEvents = new List<EventWaitHandle>();

foreach (DataObject data in dataList)
{
    // Create local variables for the thread delegate
    var threadFinish = new EventWaitHandle(false, EventResetMode.ManualReset);
    threadFinishEvents.Add(threadFinish);

    var localData = (DataObject) data.Clone();
    var thread = new Thread(
        delegate()
        {
            DoThreadStuff(localData);
            threadFinish.Set();
        }
    );
    thread.Start();
}

Mutex.WaitAll(threadFinishEvents.ToArray(), timeout);

但是，好像应该有这样的事情更简单的成语。

However, it seems like there should be a simpler idiom for this sort of thing.

推荐答案

我还是觉得用加入更简单。记录预期完成时间（如现在+超时），那么，在一个循环中，执行

I still think using Join is simpler. Record the expected completion time (as Now+timeout), then, in a loop, do

if(!thread.Join(End-now))
    throw new NotFinishedInTime();

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