将字符串转换在C＃翻番 [英] Converting string to double in C#

问题描述

我有一个double型的值（值1＃VALUE2＃VALUE3＃...）的字符串。
我把它拆分到字符串表。然后我想一个元素从该表转换为翻一番，我得到一个n错误。哪里不对？我怎样才能从这个字符串得到（字符串）在double类型的值？

 字符串= \"52.8725945#18.69872650000002#50.9028073#14.971600200000012#51.260062#15.5859949000000662452.23862099999999#19.372202799999250800000045#51.7808372#19.474096499999973#\";
字符串[] = tablicaLatLng a.Split（新的char [] {'＃'}）;
的for（int i = 0; I＆LT; tablicaLatLng.Length;我++）
{
  Console.WriteLine（tablicaLatLng [I]）;
}
Console.WriteLine（tablicaLatLng [0]）; // 52.8725945
Convert.ToDouble（tablicaLatLng [0]）; //错误
 

解决方案

在的情况下，你的第一个的双的（如你要求它）：这似乎是文化相关的问题，试试这个它应该工作（更换 与，）：

  Console.WriteLine（Convert.ToDouble（52,8725945））;
 

在这种情况下，你应该例如解析您的字符串 double.Parse ：

  double.Parse（52.8725945，System.Globalization.CultureInfo.InvariantCulture）;
 

在另一方面，你在你的字符串后面有不正确的两倍。

I have a string with double-type values ("value1#value2#value3#...). I split it to string table. Then i want to convert an element from this table to double, and I get a n error. What is wrong? How can I get from this string (string a) values in double type?

string a = "52.8725945#18.69872650000002#50.9028073#14.971600200000012#51.260062#15.5859949000000662452.23862099999999#19.372202799999250800000045#51.7808372#19.474096499999973#";
string[] tablicaLatLng = a.Split(new char[] { '#' });
for (int i = 0; i < tablicaLatLng.Length; i++)
{
  Console.WriteLine(tablicaLatLng[i]); 
}
Console.WriteLine(tablicaLatLng[0]); // 52.8725945
Convert.ToDouble(tablicaLatLng[0]); // error

解决方案

In case of your first double (as you ask for it): it seems to be culture related problem, try this it should work (replacing . with ,):

Console.WriteLine(Convert.ToDouble("52,8725945"));

In such a case you should parse your string e.g. double.Parse:

double.Parse("52.8725945", System.Globalization.CultureInfo.InvariantCulture);

On the other hand you have incorrect double later in your string.

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