为改变一个ViewModel查看 [英] Changing the View for a ViewModel
问题描述
我试图实施吨WPF应用程序的设计MVVM百通。为了将视图连接到的ViewModels,我用的,这看起来 ResourceDictionary中
(以 Application.Resources
使用)像
I am trying to implement the MVVM design patern for mt WPF application. In order to connect the view to the viewmodels, I use a ResourceDictionary
(used in Application.Resources
), that looks like
<DataTemplate DataType={x:Type viewmodel:SampleViewModel}>
<view:SampleView1 />
</DataTemplate>
视图模型,然后简单地投入内容presenters显示它们。
The view models are then simply put into content presenters to display them.
现在,当用户presses一个按钮,我想使用不同的视图来显示 SampleViewModel
。如何更改用于 SampleViewModel
?
Now, when the user presses a button, I'd like to display SampleViewModel
using a different view. How do I change the data template used for SampleViewModel
?
推荐答案
少言多code。
如你所说至于,你有类 SampleViewModel
。我加了属性标题
示范和 ViewType
确定正确的观点:
Less words more code.
As far as you said, you have the class SampleViewModel
. I added the property Title
for demonstration and ViewType
for identifying the correct view:
public enum ItemViewType { View1, View2 };
public class SampleViewModel
{
public string Title { get; set; }
public ItemViewType ViewType { get; set; }
}
的 DataTemplateSelector
为视 ViewType
属性两种观点:
class ItemViewTemplateSelector : DataTemplateSelector
{
public DataTemplate View1Template { get; set; }
public DataTemplate View2Template { get; set; }
public override DataTemplate SelectTemplate(object item, DependencyObject container)
{
var vm = item as SampleViewModel;
if (vm == null)
return null;
switch (vm.ViewType)
{
case ItemViewType.View1:
return View1Template;
case ItemViewType.View2:
return View2Template;
}
return null;
}
}
XAML中code:
Xaml code:
<Window.Resources>
<DataTemplate x:Key="view1Template">
<TextBlock Text="{Binding Title}" Foreground="Red"/>
</DataTemplate>
<DataTemplate x:Key="view2Template">
<TextBox Text="{Binding Title}" />
</DataTemplate>
<local:ItemViewTemplateSelector x:Key="viewTemplateSelector"
View1Template="{StaticResource view1Template}"
View2Template="{StaticResource view2Template}"/>
</Window.Resources>
<Window.DataContext>
<local:MainViewModel/>
</Window.DataContext>
<StackPanel>
<Button Content="ChangeView" HorizontalAlignment="Center" Command="{Binding SwitchViewCommand}"/>
<ContentControl Content="{Binding ItemViewModel}" ContentTemplateSelector="{StaticResource viewTemplateSelector}"/>
</StackPanel>
的主要部分是在类 MainViewModel
,我已经把逻辑切换视图:
The main part is in the class MainViewModel
where I've put the logic for switching views:
public class MainViewModel : ViewModelBase
{
public MainViewModel()
{
this.ItemViewModel = new SampleViewModel { Title = "Some title", ViewType = ItemViewType.View1 };
this.SwitchViewCommand = new RelayCommand(() =>
{
this.ItemViewModel.ViewType = this.ItemViewModel.ViewType == ItemViewType.View1
? ItemViewType.View2
: ItemViewType.View1;
//The magic senquence of actions which forces a contentcontrol to change the content template
var copy = this.ItemViewModel;
this.ItemViewModel = null;
this.ItemViewModel = copy;
});
}
public RelayCommand SwitchViewCommand { get; set; }
private SampleViewModel itemViewModel;
public SampleViewModel ItemViewModel
{
get { return itemViewModel; }
set
{
itemViewModel = value;
RaisePropertyChanged("ItemViewModel");
}
}
}
的 SwitchViewCommand
可以是任何类型的命令,我用命令从mvvmlight库。
The SwitchViewCommand
can be any type of command, I use the command from the mvvmlight library.
命令的处理函数中更改视图模型的类型和一个取巧的方法更新属性 ItemViewModel
,因为 ContentControl中
刷新仅当更改内容属性来看,除非你设置为不同的对象的引用此属性不会改变。
Inside the handler of the command I change the type of viewmodel and update the property ItemViewModel
in a tricky way because a ContentControl
refreshes a view only if to change the Content property, and this property will not be changed unless you set a reference to different object.
我的意思是,即使是code this.ItemViewModel = this.itemViewModel
不会改变的观点。
很奇怪,但解决方法并不需要太多的工作。
I mean, even the code this.ItemViewModel = this.itemViewModel
will not change the view.
It's strange, but the workaround doesn't require much work.
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