是否有可能不同的接口绑定到实现所有这些类的同一个实例？ [英] Is it possible to bind different interfaces to the same instance of a class implementing all of them?

问题描述

我有以下的（简化）情况：我有两个接口

I have the following (simplified) situation: I have two interfaces

interface IAmAnInterface
{
    void DoSomething();
}

和

interface IAmAnInterfaceToo
{
    void DoSomethingElse();
}

和实施这两个类：

class IAmAnImplementation: IAmAnInterface, IAmAnInterfaceToo
{
    public IAmAnImplementation()
    {
    }

    public void DoSomething()
    {
    }

    public void DoSomethingElse()
    {
    }
}

现在我同班绑定使用Ninject两个接口。因为我想的相同的实例的 IAmAnImplementation 的beeing用于 IAmAnInterface 以及 IAmAnInterfaceToo 很显然，我需要某种形式的单身人士。我 ninject.extensions.namedscope 以及发挥各地InScope（），但没有成功。我最后的尝试是：

Now I bind the same class to both interfaces using Ninject. Since I want the same instance of IAmAnImplementation beeing used for IAmAnInterface as well as IAmAnInterfaceToo it's clear that I need some kind of singleton. I played around with ninject.extensions.namedscope as well as InScope() but had no success. My last try was:

Bind<IAmAnImplementation>().ToSelf().InSingletonScope();
Bind<IAmAnInterface>().To<IAmAnImplementation>().InSingletonScope();
Bind<IAmAnInterfaceToo>().To<IAmAnImplementation>().InSingletonScope();

但不幸的是，当我通过请我的测试类的实例 kernel.Get＆LT; IDependOnBothInterfaces＆GT;（）; 它实际上使用的不同实例IAmAnImplementation 。

class IDependOnBothInterfaces
{
    private IAmAnInterface Dependency1 { get; set; }
    private IAmAnInterfaceToo Dependency2 { get; set; }

    public IDependOnBothInterfaces(IAmAnInterface i1, IAmAnInterfaceToo i2)
    {
        Dependency1 = i1;
        Dependency2 = i2;
    }

    public bool IUseTheSameInstances
    {
        get { return Dependency1 == Dependency2; } // returns false
    }
}

有没有办法告诉Ninject使用 IAmAnImplementation 的同一个实例为 IAmAnInterface 以及 IAmAnInterfaceToo ？

推荐答案

这是很容易使用V3.0.0

It is very easy using V3.0.0

Bind<I1, I2, I3>().To<Impl>().InSingletonScope();

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