如何检查是否图像对象是同为一个从资源？ [英] How to check if image object is the same as one from resource?

问题描述

所以我想创建一个简单的程序，只是改变了图片在一个图片框中单击时。我只用两张图片的时刻，所以我的图片框点击事件函数
的代码看起来像：

 私人无效pictureBox1_Click（对象发件人，EventArgs五）
 {
如果（pictureBox1.Image == Labirint.Properties.Resources.first）
 pictureBox1.Image = Labirint.Properties.Resources。 reitmi; 
，否则如果（pictureBox1.Image == Labirint.Properties.Resources.reitmi）
 pictureBox1.Image = Labirint.Properties.Resources.first; 
} 
  

由于某些原因，if语句它不工作正常，图像没有变化。
我应该怎么办？

---

请注意：原代码包含的错误与第二个如果撤消效果第一，如果条件的将会的与修复工作由 Cyral的回答，但添加其他没有解决的问题 - 通过与其他步进仍然没有显示出对于任何一个图像匹配

$ b $。 b

 如果（pictureBox1.Image == Labirint.Properties.Resources.first）
 pictureBox1.Image = Labirint.Properties.Resources.reitmi; 
如果（pictureBox1.Image == Labirint.Properties.Resources.reitmi）//失踪别的
 pictureBox1.Image = Labirint.Properties.Resources.first; 
  

解决方案

 如果（ pictureBox1.Image == Labirint.Properties.Resources.first）
  

这里有没有足够的陷阱。 .NET程序员都知道的。负责的很多的那臃肿的内存空间运行的程序。使用Labirint.Properties.Resources.xxxx属性创建一个新图片对象，它永远不会匹配任何其它图像。你需要在你的类的字段使用属性只有一次，存储图像。大致为：

 私人形象第一; 
私人图片reitmi; 
 
公共Form1的（）{
的InitializeComponent（）; 
第一= Labirint.Properties.Resources.first; 
 reitmi = Labirint.Properties.Resources.reitmi; 
 pictureBox1.Image =第一; 
} 
  

和现在你可以对它们进行比较：

 私人无效pictureBox1_Click（对象发件人，EventArgs五）{
如果（pictureBox1.Image ==第一）pictureBox1.Image = reitmi; 
，否则pictureBox1.Image =第一; 
} 
  

和避免记忆膨胀：

 私人无效Form1_FormClosed（对象发件人，FormClosedEventArgs E）{
 first.Dispose（）; 
 reitmi.Dispose（）; 
} 
  

So I'm trying to create a simple program that just change the picture in a picture box when it's clicked. I'm using just two pictures at the moment so my code for the picture box click event function looks like that:

private void pictureBox1_Click(object sender, EventArgs e)
    {
       if (pictureBox1.Image == Labirint.Properties.Resources.first)
            pictureBox1.Image = Labirint.Properties.Resources.reitmi;
       else if (pictureBox1.Image == Labirint.Properties.Resources.reitmi)
            pictureBox1.Image = Labirint.Properties.Resources.first;
    }

For some reason the if statement it's not working and the picture don't change. What should I do?

---

Note: original code contained bug with second if undoing effect of first if condition would work with fix suggested by Cyral's answer, but adding else did not fix the issue - stepping through the code with else still shows no matches for either image.

if (pictureBox1.Image == Labirint.Properties.Resources.first)
    pictureBox1.Image = Labirint.Properties.Resources.reitmi;
if (pictureBox1.Image == Labirint.Properties.Resources.reitmi) // was missing else
    pictureBox1.Image = Labirint.Properties.Resources.first; 

解决方案

     if (pictureBox1.Image == Labirint.Properties.Resources.first)

There's a trap here that not enough .NET programmers are aware of. Responsible for a lot of programs that run with bloated memory footprints. Using the Labirint.Properties.Resources.xxxx property creates a new image object, it will never match any other image. You need to use the property only once, store the images in a field of your class. Roughly:

    private Image first;
    private Image reitmi;

    public Form1() {
        InitializeComponent();
        first = Labirint.Properties.Resources.first;
        reitmi = Labirint.Properties.Resources.reitmi;
        pictureBox1.Image = first;
    }

And now you can compare them:

    private void pictureBox1_Click(object sender, EventArgs e) {
        if (pictureBox1.Image == first) pictureBox1.Image = reitmi;
        else pictureBox1.Image = first;
    }

And to avoid the memory bloat:

    private void Form1_FormClosed(object sender, FormClosedEventArgs e) {
       first.Dispose();
       reitmi.Dispose();
    }

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