C＃获取过程输出运行时 [英] C# get process output while running

问题描述

反正是有重定向衍生进程的标准输出和捕获它作为其发生。我所看到的一切都只是做的过程完成后ReadToEnd的。我希望能够得到尽可能正在打印它的输出

编辑：

 私人无效ConvertToMPEG（）
 {
 //启动子进程。 
进程p =新工艺（）; 
 //重定向子进程的输出流。 
 p.StartInfo.UseShellExecute = FALSE; 
 p.StartInfo.RedirectStandardOutput = TRUE; 
 //设置文件名和参数
 p.StartInfo.Arguments =的String.Format（ - Ÿ-i \{0} \-target NTSC-DVD -sameq -s 720×480 \ {1} \，的tempDir +out.avi的tempDir +out.mpg）; 
 p.StartInfo.FileName =ffmpeg.exe; 
 //处理接收的数据
 p.OutputDataReceived + =新DataReceivedEventHandler（p_OutputDataReceived）; 
 p.Start（）; 
} 
 
无效p_OutputDataReceived（对象发件人，DataReceivedEventArgs E）
 {
的Debug.WriteLine（e.Data）; 
} 
  

解决方案

使用的从过程Process.OutputDataReceived 事件，要收到你所需要的数据

例如：

  VAR MYPROC =新工艺（）; 
 
 ... 
 myProc.StartInfo.RedirectStandardOutput = TRUE; 
 myProc.OutputDataReceived + =新DataReceivedEventHandler（MyProcOutputHandler）; 
 
：
 
私人静态无效MyProcOutputHandler（对象sendingProcess，
 DataReceivedEventArgs轮廓）
 {
 //收集sort命令的输出。 
如果（！String.IsNullOrEmpty（outLine.Data））
 {
 .... 
} 
} 
  

Is there anyway to redirect standard output of a spawned process and capture it as its happening. Everything I have seen just does a ReadToEnd after the process has finished. I would like to be able to get the output as it is being printed.

Edit:

    private void ConvertToMPEG()
    {
        // Start the child process.
        Process p = new Process();
        // Redirect the output stream of the child process.
        p.StartInfo.UseShellExecute = false;
        p.StartInfo.RedirectStandardOutput = true;
        //Setup filename and arguments
        p.StartInfo.Arguments = String.Format("-y -i \"{0}\" -target ntsc-dvd -sameq -s 720x480 \"{1}\"", tempDir + "out.avi", tempDir + "out.mpg");
        p.StartInfo.FileName = "ffmpeg.exe";
        //Handle data received
        p.OutputDataReceived += new DataReceivedEventHandler(p_OutputDataReceived);
        p.Start();
    }

    void p_OutputDataReceived(object sender, DataReceivedEventArgs e)
    {
        Debug.WriteLine(e.Data);
    }

解决方案

Use Process.OutputDataReceived event from the process, to recieve the data you need.

Example:

var myProc= new Process();

...            
myProc.StartInfo.RedirectStandardOutput = true;
myProc.OutputDataReceived += new DataReceivedEventHandler(MyProcOutputHandler);

...

private static void MyProcOutputHandler(object sendingProcess, 
            DataReceivedEventArgs outLine)
{
            // Collect the sort command output. 
    if (!String.IsNullOrEmpty(outLine.Data))
    {
      ....    
    }
}

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