LINQ和的XDocument：如何创建XML文件？ [英] LINQ and XDocument: How to create XML file?

问题描述

我在C＃中的三甲之列，变量名是 l_lstData1，l_lstData2，l_lstData3 。

I have a three List in c# ,the variable names are l_lstData1, l_lstData2, l_lstData3.

文件结构

<FileDetails>  
  <Date FileModified="29/04/2010 12:34:02" />   
  <Data Name="Data_1" DataList="India" Level="2" />   
  <Data Name="Data_2" DataList="chennai" Level="2" />   
  <Data Name="Data_3" DataList="hyderabad" Level="2" />   
  <Data Name="Data_4" DataList="calcutta" Level="2" />  
  <Data Name="Data_5" DataList="vijayawada" Level="1" /> 
  <Data Name="Data_6" DataList="cochin" Level="1" /> 
  <Data Name="Data_7" DataList="madurai" Level="0" />  
  <Data Name="Data_8" DataList="trichy" Level="0" />   
</FileDetails>

是3列出的值如下：

The Values of 3 Lists are as follows :

 l_lstData1[0] = "India";
 l_lstData1[1] = "chennai";
 l_lstData1[2] = "hyderabad";
 l_lstData1[3] = "calcutta"; 

因此​​，上述XML（元素：数据）的水平属性。有值=2

so the level attribute of the above XML(element : Data) has value="2".

 l_lstData2[0] = "vijayawada";
 l_lstData2[1] = "cochin";      

因此​​，上述XML（元素：数据）的水平属性。有值=1

so the level attribute of the above XML(element : Data) has value="1".

 l_lstData3[0] = "madurai";
 l_lstData3[1] = "trichy";      

因此​​，上述XML（元素：数据）的水平属性。有值=0

so the level attribute of the above XML (element: Data) has value="0".

推荐答案

目前尚不清楚确切的为什么的的级别属性符合规定，但是这将创建有关XML为您提供：

It's not clear exactly why the "Level" attributes are as specified, but this would create the relevant XML for you:

// Used for side-effects in the XElement constructor. This is a bit icky. It's
// not clear what the "Name" part is really for...
int count = 1;

var doc = new XDocument(
    new XElement("FileDetails",
        new XElement("Date", new XAttribute("FileModified", DateTime.UtcNow)),
        l_lstData1.Select(x => new XElement("Data",
            new XAttribute("Name", "Data_" + count++),
            new XAttribute("DataList", x),
            new XAttribute("Level", 2))),
        l_lstData2.Select(x => new XElement("Data",
            new XAttribute("Name", "Data_" + count++),
            new XAttribute("DataList", x),
            new XAttribute("Level", 1))),
        l_lstData3.Select(x => new XElement("Data",
            new XAttribute("Name", "Data_" + count++),
            new XAttribute("DataList", x),
            new XAttribute("Level", 0)))));

这很可能是整洁，如果你可以提取一个列表项的预测，以它的元素，但DATA_+计数位使得那个棘手。为什么你需要这样的事情，说实话......如果你能逃脱不说，代码可以清洁目前尚不清楚。

It would probably be neater if you could extract the projections from a list item to its element, but the "Data_" + count bit makes that tricky. It's not clear why you need such a thing to be honest... if you could get away without that, the code could be cleaner.

我想一个选择是来创建文档的没有的的名称属性，然后填充它们之后。例如：

I suppose one alternative would be to create the document without the Name attributes, and then populate them afterwards. For example:

private static IEnumerable<XElement> ProjectList(IEnumerable<string> list,
    int level)
{
    return list.Select(x => new XElement("Data",
        new XAttribute("DataList", x),
        new XAttribute("Level", level)));
}

然后：

then:

var doc = new XDocument(
    new XElement("FileDetails",
        new XElement("Date", new XAttribute("FileModified", DateTime.UtcNow)),
        ProjectList(l_lstData1, 2),
        ProjectList(l_lstData2, 1),
        ProjectList(l_lstData3, 0)));

int count = 1;
foreach (var element in doc.Descendants("Data"))
{
    element.SetAttributeValue("Name", "Data_" + count++);
}

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