C＃，十六进制和有符号整数 [英] C#, hexadecimal notation and signed integers

问题描述

这是一个跟进问题。

所以，Java软件商店在补码加到补，你可以做以下内容：

So, Java store's integers in two's-complements and you can do the following:

int ALPHA_MASK = 0xff000000;

在C＃中，这需要使用一个无符号整数，UINT，因为它解释这是4278190080，而不是的-16777216。

In c# this requires the use of an unsigned integer, uint, because it interprets this to be 4278190080 instead of -16777216.

我的问题，如何在C＃中声明十六进制负值，以及如何准确是整数内部表示？什么是对Java这里的区别在哪里？

My question, how do declare negative values in hexadecimal notation in c#, and how exactly are integers represented internally? What are the differences to Java here?

推荐答案

C＃（更确切地说，.NET）还采用了二进制补码，但它同时支持符号和无符号类型（的Java不）。位掩码是更自然的无符号的东西 - ？为什么一位比所有其他位不同

C# (rather, .NET) also uses the two's complement, but it supports both signed and unsigned types (which Java doesn't). A bit mask is more naturally an unsigned thing - why should one bit be different than all the other bits?

在这种特殊情况下，可以安全使用一个未经检查的投

In this specific case, it is safe to use an unchecked cast:

INT ALPHA_MASK =选中（（INT）0xFF000000）;

int ALPHA_MASK = unchecked((int)0xFF000000);

编辑（添加）：

要直接代表这个数字作为符号的值，你写

To "directly" represent this number as a signed value, you write

INT ALPHA_MASK = -0x1000000; // == -16777216

int ALPHA_MASK = -0x1000000; // == -16777216

十六进制不（或不应该）从十进制什么不同：代表一个负数，你需要写一个负号，后面由代表的绝对值的数位

Hexadecimal is not (or should not) be any different from decimal: to represent a negative number, you need to write a negative sign, followed by the digits representing the absolute value.

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