如何获得字符串的XML节点值 [英] How to get the xml node value in string
问题描述
我试过下面的代码来获取特定节点的值,但在加载此抛出异常的XML:
例外:
数据在根级别无效。 1号线,位置1。
块引用>
XML
<?XML版本=1.0>?;
<数据的xmlns:XSD =http://www.w3.org/2001/XMLSchema中的xmlns:XSI =http://www.w3.org/2001/XMLSchema-instance>
<日期和GT; 2013年11月7日< /日期和GT;
<&START_TIME GT;下午01:37:11< / START_TIME>
<&END_TIME GT;下午01:37:14< / END_TIME>
将; TOTAL_TIME> 00:00:03&下; / TOTAL_TIME>
< Interval_Time />
将; Worked_Time> 00:00:03&下; / Worked_Time>
< Short_Fall> 08:29:57< / Short_Fall>
将; Gain_Time> 00:00:00&下; / Gain_Time>
< /数据>
C#:
XmlDocument的XML =新的XmlDocument();
文件路径= @D:\Work_Time_Calculator\10-07-2013.xml
xml.LoadXml(文件路径); //异常发生在这里
XmlNode的节点= xml.SelectSingleNode(/数据[@ *] / Short_Fall);
字符串ID =节点[Short_Fall]的InnerText。
修改代码
C#:
XmlDocument的XML =新的XmlDocument();
文件路径= @D:\Work_Time_Calculator\10-07-2013.xml
与XML.load(文件路径);
XmlNode的节点= xml.SelectSingleNode(/数据[@ *] / Short_Fall);
字符串ID =节点[Short_Fall]的InnerText。 //异常发生在这里(对象引用不设置到对象的实例。)
解决方案在你的代码的问题是xml.LoadXml(文件路径);
loadXML的方法取参数为XML数据不是XML文件路径
块引用>
试试这个代码
字符串XMLFILE = File.ReadAllText(@D:\Work_Time_Calculator\10-07-2013.xml);
的XmlDocument xmlDoc中=新的XmlDocument();
xmldoc.LoadXml(XMLFILE);
XmlNodeList中节点列表= xmldoc.GetElementsByTagName(Short_Fall);
串Short_Fall =的String.Empty;
的foreach(在节点列表XmlNode的节点)
{
Short_Fall = node.InnerText;
}
修改
看到你的问题的最后编辑我找到了解决办法,
只需更换低于2行
XmlNode的节点= xml.SelectSingleNode(/数据[@ *] / Short_Fall);
字符串ID =节点[Short_Fall]的InnerText。 //异常发生在这里(对象引用不设置到对象的实例。)
与
字符串ID = xml.SelectSingleNode(数据/ Short_Fall)的InnerText。
它应该解决您的问题,或者你可以使用我先前提供的解决方案。
I tried the below code to get the value of a particular node, but while loading the xml this exception is thrown:
Exception:
Data at the root level is invalid. Line 1, position 1.
XML
<?xml version="1.0"?> <Data xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <Date>11-07-2013</Date> <Start_Time>PM 01:37:11</Start_Time> <End_Time>PM 01:37:14</End_Time> <Total_Time>00:00:03</Total_Time> <Interval_Time/> <Worked_Time>00:00:03</Worked_Time> <Short_Fall>08:29:57</Short_Fall> <Gain_Time>00:00:00</Gain_Time> </Data>
C#:
XmlDocument xml = new XmlDocument(); filePath = @"D:\Work_Time_Calculator\10-07-2013.xml"; xml.LoadXml(filePath); // Exception occurs here XmlNode node = xml.SelectSingleNode("/Data[@*]/Short_Fall"); string id = node["Short_Fall"].InnerText;
Modified Code
C#:
XmlDocument xml = new XmlDocument(); filePath = @"D:\Work_Time_Calculator\10-07-2013.xml"; xml.Load(filePath); XmlNode node = xml.SelectSingleNode("/Data[@*]/Short_Fall"); string id = node["Short_Fall"].InnerText; // Exception occurs here ("Object reference not set to an instance of an object.")
解决方案The problem in your code is xml.LoadXml(filePath);
LoadXml method take parameter as xml data not the xml file path
Try this code
string xmlFile = File.ReadAllText(@"D:\Work_Time_Calculator\10-07-2013.xml"); XmlDocument xmldoc = new XmlDocument(); xmldoc.LoadXml(xmlFile); XmlNodeList nodeList = xmldoc.GetElementsByTagName("Short_Fall"); string Short_Fall=string.Empty; foreach (XmlNode node in nodeList) { Short_Fall = node.InnerText; }
Edit
Seeing the last edit of your question i found the solution,
just replace the below 2 line
XmlNode node = xml.SelectSingleNode("/Data[@*]/Short_Fall"); string id = node["Short_Fall"].InnerText; // Exception occurs here ("Object reference not set to an instance of an object.")
with
string id = xml.SelectSingleNode("Data/Short_Fall").InnerText;
it should solve your problem or you can use the solution i provided earlier.
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