最小长度正则表达式 [英] Minimum Length Regular Expression

问题描述

我想写一个正则表达式将会验证用户输入比非空白字符X数字更大。我基本上是试图筛选出开始时和结束的空白，同时还确保输入超过X个字符;字符可以是任何东西，只是没有空格（空格，制表符，换行符）。
这是我一直在使用正则表达式，但它不工作：

I'm trying to write a regular expression that will validate that user input is greater than X number of non-whitespace characters. I'm basically trying to filter out begining and ending whitespace while still ensuring that the input is greater than X characters; the characters can be anything, just not whitespace (space, tab, return, newline). This the regex I've been using, but it doesn't work:

\s.{10}.*\s

我使用C＃4.0（Asp.net正则表达式验证）BTW 。如果该事项

I'm using C# 4.0 (Asp.net Regular Expression Validator) btw if that matters.

推荐答案

这可能是更容易不使用正则表达式都：

It may be easier to not use regex at all:

input.Where(c => !char.IsWhiteSpace(c)).Count() > 10

如果空白不应该在中间算的话，这将工作：

If whitespace shouldn't count in the middle, then this will work:

(\s*(\S)\s*){10,}

如果您没有在非空格字符之间关心的空白，其他的答案有一个场景覆盖。

If you don't care about whitespace in between non-whitespace characters, the other answers have that scenario covered.

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