启动默认浏览器与HTML文件，然后跳转到特定的锚 [英] Launching default browser with html from file, then jump to specific anchor

问题描述

我需要打开从程序根目录下的HTML文件，并把它跳转到指定的锚。我可以打开该文件用一个简单的

I need to open an html file from the program root directory and have it jump to a specified anchor. I can open the file perfectly fine with a simple

System.Diagnostics.Process.Start（site.html）

System.Diagnostics.Process.Start("site.html")

但只要我尝试锚添加到它不再能够找到该文件的末尾。

but as soon as I try to add the anchor to the end it ceases to be able to find the file.

我能够把锚那里仍然有它以

I was able to put the anchor in there and still have it launch with

字符串锚

锚=启动文件：///+环境。.CurrentDirectory.ToString（）更换（\，/）+
/site.html#Anchor
System.Diagnostics.Process.Start（锚）;

Anchor = "file:///" + Environment.CurrentDirectory.ToString().Replace("\", "/") + "/site.html#Anchor"; System.Diagnostics.Process.Start(Anchor);

然而只要浏览器启动则丢弃该锚。有什么建议？

However as soon as the browser launches it drops the anchor. Any suggestions?

推荐答案

您可能需要包含整个URL引号中保存任何特殊字符（如＃） 。或空格

You may need to enclose the entire URL in quotation marks to preserve any special characters (such as the #) or spaces.

尝试：

string Anchor = String.Format("\"file:///{0}/site.html#Anchor\"", Environment.CurrentDirectory.ToString().Replace("\\", "/"));
System.Diagnostics.Process.Start(Anchor);

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