的XDocument它的name属性的值获取XML元素 [英] XDocument get XML element by the value of its name attribute

问题描述

我有一个 XML 造成这样

<response>
  <lst name="responseHeader">
    <int name="status">0</int>
    <int name="QTime">16</int>
  </lst>
  <result name="response" numFound="3" start="0" maxScore="1.0">
    <doc>
      <str name="ContaFirstname">
        firstname1                                                   
      </str>
      <str name="ContaId">6557</str>
      <str name="ContaJobTitle">Manager</str>
      <str name="ContaSurname">surname1
      </str>
    </doc>
    <doc>
      <str name="ContaFirstname">firstname2</str>
      <str name="ContaId">6203</str>
      <str name="ContaJobTitle">Director</str>
      <str name="ContaSurname">surname2</str>
    </doc>
  </result>
</response>

我想获得对象的列表，每个对象将包含<$ C $的价值C> ContaFirstname ， ContaId ， ContaJobTitle 和 ContaSurname

我想这样的事情，但是这是不正确的，因为我让他们所有NULL

I tried something like this, but that's not right because I get them all NULL

var test = from c in xml.Descendants("doc")
                    select new 
                    {
                        firstname = c.Element("ContaFirstname"),
                        surnmane = c.Element("ContaSurname")
                    }; 

那么，如何可以按名称访问这些元素？

So how can access these elements by name?

推荐答案

您不想来访问的名称的，因为大多数人会理解这句话的元素。你想通过自己的名称的值来访问元素属性：

You don't want to access the elements by name as most people would interpret that statement. You want to access the elements by the value of their name attribute:

firstname = (string) c.Elements("str")
                      .First(x => x.Attribute("name").Value == "ContaFirstname");
//etc

您可能想抽象的到一个单独的方法，因为它是将是一个痛苦的多次做。例如：

You may well want to abstract that into a separate method, as it's going to be a pain to do it multiple times. For example:

public static XElement ElementByNameAttribute(this XContainer container,
                                              string name)
{
    return container.Elements("str")
                    .First(x = x.Attribute("name").Value == name);
}

然后：

Then:

var test = from c in xml.Descendants("doc")
           select new 
           { 
               firstname = c.ElementByNameAttribute("ContaFirstname").Value,
               surnmane = c.ElementByNameAttribute("ContaSurname").Value
           }; 

如果您有任何的机会，让您的文档更合理的结构，这将是最好...

If you have any chance to give your document a more sensible structure, that would be preferable...

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