怎样声明函数求代表返回相同类型的函数求代表？ [英] How do I declare a Func Delegate which returns a Func Delegate of the same type?

问题描述

我喜欢写，做一些工作，最后返回具有相同签名与原始方法的另一种方法的方法。我们的想法是处理取决于前一字节值顺序的字节流，而不进入一个递归。通过调用它是这样的：

I'd like to write a method which does some work and finally returns another method with the same signature as the original method. The idea is to handle a stream of bytes depending on the previous byte value sequentially without going into a recursion. By calling it like this:

MyDelegate executeMethod = handleFirstByte //What form should be MyDelegate?

foreach (Byte myByte in Bytes)
{
    executeMethod = executeMethod(myByte); //does stuff on byte and returns the method to handle the following byte
}

要交接方法我想将它们分配给函数求委托。但是，我跑进这会导致一个递归声明没有终止...

To handover the method I want to assign them to a Func delegate. But I ran into the problem that this results in a recursive declaration without termination...

Func<byte, Func<byte, <Func<byte, etc... >>>

我莫名其妙地丢在这里。 ？我怎么能解决这个让

I'm somehow lost here. How could I get around that?

推荐答案

您可以简单地声明一个委托类型时，预定义的 Func键< ...> 代表是不够的：

You can simply declare a delegate type when the predefined Func<...> delegates aren't sufficient:

public delegate RecursiveFunc RecursiveFunc(byte input);

而如果你需要它，你可以使用泛型太：

And in case you need it, you can use generics too:

public delegate RecursiveFunc<T> RecursiveFunc<T>(T input);

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