使用HTMLAgilityPack节点的儿童;选择全部< P&GT [英] Select all <p>'s from a Node's children using HTMLAgilityPack

问题描述

我有下面的代码，我使用得到一个HTML页面。使绝对的URL，然后使链接REL nofollow的，开放的新窗口/标签。我的问题是周围的属性添加到<一个方式> 取值

I've got the following code that I'm using to get a html page. Make the urls absolute and then make the links rel nofollow and open in a new window/tab. My issue is around the adding of the attributes to the <a>s.

        string url = "http://www.mysite.com/";
        string strResult = "";            

        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
        HttpWebResponse response = (HttpWebResponse)request.GetResponse();

        if ((request.HaveResponse) && (response.StatusCode == HttpStatusCode.OK)) {
            using (StreamReader sr = new StreamReader(response.GetResponseStream())) {
                strResult = sr.ReadToEnd();
                sr.Close();
            }
        }

        HtmlDocument ContentHTML = new HtmlDocument();
        ContentHTML.LoadHtml(strResult);
        HtmlNode ContentNode = ContentHTML.GetElementbyId("content");

        foreach (HtmlNode node in ContentNode.SelectNodes("/a")) {
            node.Attributes.Append("rel", "nofollow");
            node.Attributes.Append("target", "_blank");
        }

        return ContentNode.WriteTo();

任何人都可以看到我在做什么错？去过尝试了一段时间这里没有运气。此代码出现该ContentNode.SelectNodes（/ a）的未设置为一个对象的一个​​实例。我虽然尝试和蒸汽设置为0？

Can anyone see what I'm doing wrong? Been try for a while here with no luck. This code comes up that ContentNode.SelectNodes("/a") isn't set to an instance of an object. I though to try and set the steam to 0?

干杯，
丹尼斯

Cheers, Denis

推荐答案

是 ContentNode 空？您可能需要选择单与查询// * [@ ID ='内容']。

Is ContentNode null? You might need to select-single with the query "//*[@id='content']".

有关信息， 表示所有锚在根。确实后裔::一个工作？还有 HtmlElement.GetElementsByTagName 这可能是更容易 - 即 yourElement.GetElementsByTagName（A）

For info, "/a" means all anchors at the root. does "descendant::a" work? There is also HtmlElement.GetElementsByTagName which might be easier - i.e. yourElement.GetElementsByTagName("a").

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