使用基类一般为IEnumerable的< T> [英] Using base class as generic for IEnumerable<T>

问题描述

我在一般情况下，继承和多态，接口等OOP很好地理解我遇到了一个奇怪的情况，我不明白为什么它不工作在所有...

I have a good understanding of OOP in general, inheritance and polymorphism, interfaces, etc. I encountered a strange situation and I don't understand why it does not work at all...

编辑：好吧，我发现，协方差（或逆变？）可以解决这个问题，但关键

EDIT : Ok, I found out that covariance (or contravariance?) may solve this problem, but crucially

我怎么能解决这个问题没有移动到C＃4.0？

How can I solve this without moving to C# 4.0 ?

这里的情况。鉴于这两个类：

Here is the situation. Given these two classes :

public class CustomCollectionType<T> : IEnumerable<T>
{
    /* Implementation here, not really important */
}

public class Entity : EntityBase
{
    /* Implentation here, not important */
}

编译器会抱怨，当我尝试这个泛型方法

The compiler complains when I try to have this generic method

public void LoopThrough(IEnumerable<EntityBase> entityList)
{
    foreach(EntityBase entity in entityList) 
    {
        DoSomething(entity);  
    }
}

和尝试用这种方式：

CustomCollectionType<Entity> entityList;
/* Add items to list */

LoopThrough(entityList);

错误说我不能从 CustomCollectionType<转化;实体> 到的IEnumerable< EntityBase>

不过，我可以做到这一点：

However, I can do this :

public void Foo(EntityBase entity)
{
    entity.DoSomething();
}

Foo(new Entity());

和这样的：

public void Bar(IEnumerable<Entity> entityList)
{ ... }

CustomCollectionType<Entity> entityList;

Bar(entityList);

为什么我不能创建我的方法与层次结构中的最高等级？类型显然兼容...我缺少的东西。

Why can't I create my method with the highest classes in the hierarchy? The types are obviously compatible... Am I missing something ?

编辑：？我想不会以任何方式改变现有的类来解决这个问题，因此创建一个新方法在任何一个类，或者实现额外的接口是出了问题。

EDIT : I want to solve this problem without altering the existing classes in any way, so creating a new method in any of the classes, or implementing an additional interface is out of the question.

推荐答案

让我们看看你的第一个案例。您有：

Let's consider your first case. You have:

class Bowl<T> : IEnumerable<T> {}
class Apple : Fruit {}
...
void LoopThrough(IEnumerable<Fruit> fruits) ...

和你打电话

Bowl<Apple> apples = whatever;
LoopThrough(apples);

这失败的C＃3.0;它成功在C＃4.0，因为的IEnumerable< T> 现在是在协变笔;苹果的序列，可作为水果的序列。

This fails in C# 3.0; it succeeds in C# 4.0 because IEnumerable<T> is now covariant in T; a sequence of apples can be used as a sequence of fruits.

要使其在工作，C＃3.0，你可以使用铸造序列算

To make it work in C# 3.0 you can use the Cast sequence operator.

Bowl<Apple> apples = whatever;
LoopThrough(apples.Cast<Fruit>());

要使其工作在C＃2.0，实施播序列运营商自己的。它是代码只有几行

To make it work in C# 2.0, implement the Cast sequence operator yourself. It is only a couple lines of code.

请注意，在C＃4.0中它仍然是不合法的说：

Note that in C# 4.0 it will still not be legal to say:

Bowl<Fruit> fruits = new Bowl<Apples>();

由于你当然可以说：

fruits.Add(new Orange());

和你只要把一个橘子放入碗中只能包含苹果。

and you just put an orange into a bowl that can only contain apples.

这篇关于使用基类一般为IEnumerable的< T>的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！