我如何才能找到在C#2值之间的差异? [英] How can I find the difference between 2 values in C#?
问题描述
我与10.000000和-10.000000之间波动的振荡器工作
价值的变化,每5分钟说。我想找到当前值和的5分钟前的值之间的差。这是我的逻辑。
1巴前(1BA)= -.2
当前条(CB)= 0.3
难道我得到的值为1,如果我不喜欢的东西:
ABS(CB) - ABS(1BA)= 0.3 - 0.2 = 1
鉴于:
ABS(CB-1BA)= 0.3 - -.2 = 5
我想简单计算振荡器的移动从一个时间帧到另一个之间的差。 ?我是应用在ABS与正确的逻辑记
下面是我实际的代码,请假设我的方法被称为是正确的:
如果(振荡器(PoFast,PoSlow,PoSmooth)[0]>
振荡器(PoFast,PoSlow,PoSmooth)[3]
&功放;&安培; Math.Abs(振荡器(PoFast,PoSlow,PoSmooth)[0] -
振荡器(PoFast,PoSlow,PoSmooth)[3])> 0.25)
二,ABS(CB-1BA)将是正确的,因为有一个变化.5两次读数
修改:为了使其更具可读性,假设你得到双重价值,你会怎么做这样的事情,但有错误检查,而且很可能使.25变量。
双击[] =值振荡器(PoFast ,PoSlow,PoSmooth);
双currentBar =值[0];
双oneBarAgo =值[3];
如果(currentBar> oneBarAgo和放大器;&安培; Math.Abs(currentBar - oneBarAgo)GT; 0.25)
{
//做些什么
}
I am working with an Oscillator that fluctuates between 10.000000 and -10.000000
The value changes say every 5 minutes. I want to find the difference between the current value and the value of 5 minutes ago. Here is my logic.
1 bar ago (1BA)= -.2
Current bar (CB) = .3
Wouldn't I get a value of 1 if I did something like:
Abs(CB) - Abs(1BA) = .3 - .2 = 1
Whereas:
Abs(CB- 1BA) = .3 - -.2 = 5
I want to simply calculate the difference between the move of the oscillator from one time frame to another. Am I applying the Abs with the right logic in mind?
Here is my actual code, please assume my method being called is correct:
if (Oscillator(PoFast, PoSlow, PoSmooth)[0] >
Oscillator(PoFast, PoSlow, PoSmooth)[3]
&& Math.Abs(Oscillator(PoFast, PoSlow, PoSmooth)[0] -
Oscillator(PoFast, PoSlow, PoSmooth)[3]) > .25)
Of the two, Abs(CB-1BA) would be correct, since there was a change of .5 between the two readings.
EDIT: To make it more readable, and assuming you're getting double values, you'd do something like this, but with error checking, and probably making the .25 a variable.
double[] values = Oscillator(PoFast, PoSlow, PoSmooth);
double currentBar = values[0];
double oneBarAgo = values[3];
if (currentBar > oneBarAgo && Math.Abs(currentBar - oneBarAgo) > .25)
{
// do something
}
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