与AdMob的问题 [英] Problem with admob

问题描述

OK，我曾问过类似的<一个href="http://stackoverflow.com/questions/5408336/a-common-footer-for-an-entire-application-android">question已经得到了前一个答案，但认为过于笼统的问题。

OK, I had asked a similar question before and had got an answer but that was too general a question.

现在我有一个应用程序，其中有大量的活动。每个活动已被列入其布局文件相同的AdMob（AD浏览报）布局。现在的问题是，当我从一个活动到另一个后的第一个屏幕完成加载广告，第二个活动仍在等待另一则广告中提取周期发生[即，它再次发送广告请求，并显示一个新的广告]。所有我想做的事是我的应用程序，以显示在每一个活动的广告相同的实例。 [相同的实例意思是：我有一个基于时间间隔上的广告必须刷新，所以一个新的广告请求必须在期限届满，而不是当用户从一个活动导航到另一个只发送]

Now I've an app in which there are plenty of activities. Each activity has the same admob (AdView) layout being included in its layout file. Now the problem is when I go from one activity to the other after the first screen has finished loading the ad, the second activity still waits for another ad fetch cycle to happen [ie., it again sends an ad request and displays a new ad]. All I want to do is for my app to show the same instance of the ad in every activity. [Same instance meaning: I have a time interval based on which the ads must refresh, so a new ad request must be sent only when the time limit expires, not when user navigates from one activity to another.]

有反正我可以做到这一点。我曾在前面的解决方案中提到的单身的做法，但也有很多的并发症COS每次我这样做，它说，指定的孩子已经有一个家长和调用removeView父是必要的。

Is there anyway I can do this. I have tried the "Singleton" approach mentioned in the earlier solution but there are lot of complications cos everytime I do that, it says that the specified child already has a parent and a call to removeView on the parent is necessary.

难道我做错什么（或/和）任何人可以帮助我做一些其他的解决办法？

Am I doing anything wrong (OR/AND) can anybody help me with some other solution??

我的Singleton类是在这里：

My Singleton class is here:

public class CommonAdFooter {
static final CommonAdFooter commonAdFooter = new CommonAdFooter();
static AdView admobView;
LayoutInflater LInflater;

private CommonAdFooter() {
    LInflater = (LayoutInflater) Constants.context
            .getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    admobView = (AdView) LInflater.inflate(R.layout.ad_layout, null);
    LayoutParams lp = new LayoutParams(LayoutParams.FILL_PARENT,
            LayoutParams.WRAP_CONTENT);
    lp.addRule(RelativeLayout.ALIGN_PARENT_BOTTOM);
    admobView.setLayoutParams(lp);
}

public static AdView getAdLayout() {
    return admobView;
}
}

这是我的广告布局文件

and this is my layout file for the ads

<?xml version="1.0" encoding="utf-8"?>
<com.admob.android.ads.AdView
xmlns:android="http://schemas.android.com/apk/res/android" xmlns:myapp="..."
android:id="@+id/ad" android:layout_alignParentBottom="true"
android:background="#C9E3F6" android:layout_width="fill_parent"
android:layout_height="wrap_content" myapp:backgroundColor="#006699"
myapp:primaryTextColor="#C9E3F6" myapp:secondaryTextColor="#C9E3F6" />

编辑：Admob的 API 链接添加

推荐答案

我不知道确切的语法，你能链接AdMob的API？

I'm not sure on the exact syntax, could you link the AdMob api?

但是，你得到一个错误，因为当你返回的广告版面它已经连接到previous活动。所以，你需要这样的：

But your getting an error because when you return the ad layout it is already attached to the previous activity. So you would need something like this:

<打击>公共静态AD浏览报getAdLayout（）{

<打击> admobView.removeParent（）; //或类似的见API

<打击>返回admobView;

<打击>}

修改的

啊在这里我们去： AD浏览报的JavaDoc 所以从视野和herits < A HREF =htt​​p://developer.android.com/reference/android/widget/RelativeLayout.html相对=nofollow> RelativeLayout的的伟大。

Ah here we go: AdView JavaDoc so it herits from view and RelativeLayout great.

试试这个：

public static AdView getAdLayout() {
     if(admobView.getParent() != null){
        admobView.detachAllViewsFromParent();
     }
    return admobView;
}

或

public static AdView getAdLayout() {
     if(admobView.getParent() != null){
        admobView.getParent().removeView(admobView);
     }
    return admobView;
}

答案是在JavaDoc只是有点试验和错误

The answer is in the JavaDoc just a bit of trial and error

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