嵌套类：无法访问静态情况下的非静态字段 [英] Nested class: Cannot access non-static field in static context

问题描述

我有一些内部变量C类。它有希望访问C.变量无论是C和N分别静态嵌套类N，虽然C有一些静态方法和变量。当我试图访问一个非静态变量用C从NI获得波浪下划线和消息无法访问非静态字段[字段名]在静态情况下。

这似乎有事情做与嵌套类，因为我可以访问从封闭类本身变细。

ReSharper的建议我做_t静态的，而是说ISN T选项。 ？我该如何处理这种

 公共部分的密封类C 
 {
串_t; 
 
类N 
 {
无效米（）
 {
 _t =外商投资企业; //这里出现错误
} 
} 
} 
  

解决方案

这是不是Java，而你没有的内的类。

的一个实例嵌套类不与外部类的任何实例相关联的，除非你通过存储引用（又名处理/指针）在构造函数中进行关联。

 公共部分的密封类C 
 {
串_t; 
 
类N 
 {
只读Ç外; 
 
公共N（父）{外=父母; } 
 
无效米（）
 {
 outer._t =外商投资企业; //错误走了
} 
} 
} 
  

I have a class C with some internal variables. It has a nested class N that wants to access the variables in C. Neither C nor N are static, although C has some static methods and variables. When I try to access a non-static variable in C from N I get the squiggly underline and the message "Cannot access non-static field [fieldname] in static context".

This seems to have something to do with the nested class, since I can access the variable fine from the enclosing class itself.

ReSharper suggests I make _t static but that isn't an option. How do I deal with this?

public sealed partial class C
{
    string _t;

    class N
    {
        void m()
        {
            _t = "fie"; // Error occurs here
        }
    }
}

解决方案

This isn't Java, and you don't have inner classes.

An instance of a nested class is not associated with any instance of the outer class, unless you make an association by storing a reference (aka handle/pointer) inside the constructor.

public sealed partial class C
{
    string _t;

    class N
    {
        readonly C outer;

        public N(C parent) { outer = parent; }

        void m()
        {
            outer._t = "fie"; // Error is gone
        }
    }
}

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