C＃中转换成十六进制值，UTF8和ASCII [英] C# convert hexadecimal value in to UTF8 and ASCII

问题描述

我想转换为十六进制值的字符串中两个ASCII值和UTF8价值。但是，当我执行下面的代码，它打印出相同的十六进制值，我给作为输入

 字符串十六进制串=68656c6c6f2c206d79206e616d6520697320796f752e; 
 System.Text.UTF8Encoding编码=新System.Text.UTF8Encoding（）; 
字节[] = dBytes encoding.GetBytes（十六进制串）; 
 
 //要获得十六进制字符串的ASCII值。 
串ASCIIresult = System.Text.Encoding.ASCII.GetString（dBytes）; 
 MessageBox.Show（ASCIIresult，显示在ASCII值）; 
 
 //要获得十六进制字符串
串utf8result = System.Text.Encoding.UTF8.GetString（dBytes）的UTF8价值; 
 MessageBox.Show（utf8result，显示在UTF8值）; 
  

解决方案

既然你命名一个变量十六进制串，我认为值已经编码成十六进制格式

这意味着下面的不会起作用：

 字符串十六进制串=68656c6c6f2c206d79206e616d6520697320796f752e; 
 System.Text.UTF8Encoding编码=新System.Text.UTF8Encoding（）; 
字节[] = dBytes encoding.GetBytes（十六进制串）; 
  

这是因为你是治疗已编码的字符串作为纯UTF8文本。

您很可能缺少一个步骤，以十六进制编码字符串转换成字节数组转换。

您可以在此使用的this SO帖子这说明此功能：

 公共静态的byte [] StringToByteArray（十六进制字符串）
 {
 INT NumberChars = hex.Length / 2; 
字节[]字节=新的字节[NumberChars] 
使用（VAR SR =新StringReader（十六进制））
 {
的for（int i = 0; I< NumberChars;我++）
字节[i] = 
 Convert.ToByte（新的字符串（新的char [2] {（char）的sr.Read（），（炭）sr.Read（）}），16）; 
} 
返回字节; 
} 
  

所以，最终的结果会是这样的：

 字节[] = dBytes StringToByteArray（十六进制串）; 
 
 //要获得十六进制字符串的ASCII值。 
串ASCIIresult = System.Text.Encoding.ASCII.GetString（dBytes）; 
 MessageBox.Show（ASCIIresult，显示在ASCII值）; 
 
 //要获得十六进制字符串
串utf8result = System.Text.Encoding.UTF8.GetString（dBytes）的UTF8价值; 
 MessageBox.Show（utf8result，显示在UTF8值）; 
  

I am trying to convert a hexadecimal values in a string in to both ASCII value and UTF8 value. But when I execute the following code, it prints out the same hex value I give as input

string hexString = "68656c6c6f2c206d79206e616d6520697320796f752e";
System.Text.UTF8Encoding  encoding=new System.Text.UTF8Encoding();
byte[] dBytes = encoding.GetBytes(hexString);

//To get ASCII value of the hex string.
string ASCIIresult = System.Text.Encoding.ASCII.GetString(dBytes);
MessageBox.Show(ASCIIresult, "Showing value in ASCII");

//To get the UTF8 value of the hex string
string utf8result = System.Text.Encoding.UTF8.GetString(dBytes);
MessageBox.Show(utf8result, "Showing value in UTF8");

解决方案

Since you are naming a variable hexString, I assume that the value is already encoded into a hex format.

This means the following will not work:

string hexString = "68656c6c6f2c206d79206e616d6520697320796f752e";
System.Text.UTF8Encoding  encoding=new System.Text.UTF8Encoding();
byte[] dBytes = encoding.GetBytes(hexString);

This is because you are treating the already encoded string as plain UTF8 text.

You are probably missing a step to convert the hex encoded string into a byte array.

You can do this using this SO post which shows this function:

public static byte[] StringToByteArray(String hex)
{
  int NumberChars = hex.Length/2;
  byte[] bytes = new byte[NumberChars];
  using (var sr = new StringReader(hex))
  {
    for (int i = 0; i < NumberChars; i++)
      bytes[i] = 
        Convert.ToByte(new string(new char[2]{(char)sr.Read(), (char)sr.Read()}), 16);
  }
  return bytes;
}

So, the end result would be this:

byte[] dBytes = StringToByteArray(hexString);

//To get ASCII value of the hex string.
string ASCIIresult = System.Text.Encoding.ASCII.GetString(dBytes);
MessageBox.Show(ASCIIresult, "Showing value in ASCII");

//To get the UTF8 value of the hex string
string utf8result = System.Text.Encoding.UTF8.GetString(dBytes);
MessageBox.Show(utf8result, "Showing value in UTF8");

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