在空白忽视paranthesis将字符串分割 [英] Split string on whitespace ignoring paranthesis

问题描述

我有一个字符串，如本

(ed) (Karlsruhe Univ. (TH) (Germany, F.R.))

我需要把它分成两个像这样

I need to split it into two such as this

ed
Karlsruhe Univ. (TH) (Germany, F.R.)

基本上，paranthesis中忽略空格和paranthesis

Basically, ignoring whitespace and paranthesis within a paranthesis

是否有可能使用正则表达式，如果你能做到这一点？

Is it possible to use a regex to achieve this?

推荐答案

有更多的括号，这是更好地使用均衡组：

If you can have more parentheses, it's better to use balancing groups:

string text = "(ed) (Karlsruhe Univ. (TH) (Germany, F.R.))";
var charSetOccurences = new Regex(@"\(((?:[^()]|(?<o>\()|(?<-o>\)))+(?(o)(?!)))\)");
var charSetMatches = charSetOccurences.Matches(text);
foreach (Match match in charSetMatches)
{
    Console.WriteLine(match.Groups[1].Value);
}

的 ideone演示

分析：

\((                     # First '(' and begin capture
    (?:                 
    [^()]               # Match all non-parens
    |
    (?<o> \( )          # Match '(', and capture into 'o'
    |
    (?<-o> \) )         # Match ')', and delete the 'o' capture
    )+
    (?(o)(?!))          # Fails if 'o' stack isn't empty

)\)                     # Close capture and last opening brace

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