创建函数SWIG C＃包装包含void *的参数 [英] Create SWIG C# wrapper for function that contains void* parameter

问题描述

我试图创建一个包含函数需要使用痛饮拿一个空指针是C的.lib一个C＃包装。

I'm trying to create a C# wrapper for a C .lib that contains functions take take a void pointer using SWIG.

int inputPointExample(void* input);
int outputPointerExample(void* output);

默认情况下痛饮不处理空指针的转换，你必须以某种方式使用typemaps。我发现这个页面 - > http://www.nickdarnell.com/ 2011/05 /痛饮和-A-小姐/
9号说，使用下面的typemaps处理空指针...

By default SWIG doesn't handle void pointer conversions, you have to use typemaps somehow. I found this page -> http://www.nickdarnell.com/2011/05/swig-and-a-miss/ Number 9 says to use the following typemaps to handle void pointers...

%typemap(ctype)  void * "void *"
%typemap(imtype) void * "IntPtr"
%typemap(cstype) void * "IntPtr"
%typemap(csin)   void * "$csinput"
%typemap(in)     void * %{ $1 = $input; %}
%typemap(out)    void * %{ $result = $1; %}
%typemap(csout)  void * { return $imcall; }

当我尝试，我在我的exampleVectorType.cs得到一个编译错误此功能...

When I try that I get a compile error in my exampleVectorType.cs in this function...

public IntPtr pData {
set {
  examplePINVOKE.ExampleVectorType_pData_set(swigCPtr, value);
} 
get {
  global::System.IntPtr cPtr = examplePINVOKE.ExampleVectorType_pData_get(swigCPtr);
  SWIGTYPE_p_void ret = (cPtr == global::System.IntPtr.Zero) ? null : new SWIGTYPE_p_void(cPtr, false);
  return ret; //Compile error occurs here
    } 
}

我 -

I got-

Cannot implicitly convert type 'SWIGTYPE_p_void' to 'System.IntPtr'

这是我能找到，还有许多人有这个问题，以及有的只是关于如何解决这几个可怜的例子。有人可以帮助我在这里？

From what I was able to find, many others are having problems with this as well and there are only a few poor examples on how to fix this. Can someone help me out here?

推荐答案

我和

// c++
void* GetRawPtr()
{
    return (void*)_data;
}

这swigs到

which swigs to

// swig generated c#
// Example.cs
IntPtr GetRawPtr()
{
    return examplePINVOKE.Example_GetRawPtr(swigCPtr);
} 

// examplePINVOKE.cs
[global::System.Runtime.InteropServices.DllImport("example", EntryPoint="CSharp_Example_GetRawPtr")]
public static extern IntPtr Example_GetRawPtr(global::System.Runtime.InteropServices.HandleRef jarg1);

如果下面的行被删除，然后我让你有代码：

if the following line is removed, then i get the code you had:

%typemap(csout)  void * { return $imcall; }

也许痛饮不支持使用性能typemapping好？如果你不为你的pData使用get /设置属性，它应该工作（因为我已经得到它为我工作）

perhaps SWIG doesn't support typemapping well with properties? If you don't use get/set properties for your pData, it should work (as I've gotten it to work for me)

这篇关于创建函数SWIG C＃包装包含void *的参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！