在Prism地区激活视图 [英] Activating views in regions in Prism
问题描述
我有问题,我似乎无法解决。我有一个创建了一个测试项目,使用MEF和Prism4。我创建了一个测试项目,其中我有2个视图,每个注册自己在一个区域内,还有一个按钮在另一个地区。当点击按钮时,我想要更改的视图到正确的视图。我认为错误的代码如下,任何人都有任何想法我在这里做错了什么?
I have problem that I don't seem to be able to solve. I have a created a test project, using MEF and Prism4. I've created a test project where I have 2 views and each of them register themselves inside a region, and also a button in another region. When the button is clicked, I want the view of change to the correct view. The code I think is wrong is below, anyone have any ideas what I am doing wrong here ?
public void Initialize()
{
regionManager.RegisterViewWithRegion(RegionNames.MainRegion, typeof(Views.Module1View));
Button button = new Button() { Content = "Module1" };
button.Click += (o, i) =>
{
var region = this.regionManager.Regions[RegionNames.MainRegion];
if (region != null)
{
region.Activate(typeof(Views.Module1View));
}
};
regionManager.AddToRegion(RegionNames.NavigationRegion, button);
}
我收到以下错误...
I get the following error ...
The region does not contain the specified view.
Parameter name: view
推荐答案
惊人什么一个良好的夜晚睡眠会做!我不得不从ServiceLocator获取视图。
Solved it - amazing what a good nights sleep will do! I had to get the view from the ServiceLocator.
public void Initialize()
{
regionManager.RegisterViewWithRegion(RegionNames.MainRegion, () =>
ServiceLocator.Current.GetInstance<Views.Module2View>());
Button button = new Button() { Content = "Module2" };
button.Click += (o, i) =>
{
var view = ServiceLocator.Current.GetInstance<Views.Module2View>();
var region = this.regionManager.Regions[RegionNames.MainRegion];
if (region != null)
{
region.Activate(view);
}
};
regionManager.AddToRegion(RegionNames.NavigationRegion, button);
}
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