c＃Regex-删除只开发特殊章程组合的字符串 [英] c# Regex- Remove string which developed only combination of special charter

问题描述

我正在寻找正则表达式，我可以忽略只是所有特殊章程组合的字符串。

示例

 列表< string> liststr = new List< string>（）{a b，c％d，，％％％％，''，&，'' etc ... 
  

我需要这个结果

  {ab，c％d} 
  

 。[A-Za-z0- 9]。* 
  

它至少匹配一个字母数字字符。这样做，它将采取任何字符串，不仅是符号/特殊字符。它执行您想要的输出，请参阅：演示

I am looking for regular expression by which I can ignore strings which is only combination of All special charters.

Example

List<string> liststr = new List<string>() { "a b", "c%d", " ", "% % % %" ,"''","&","''","'"}; etc...

I need result of this one

{ "a b", "c%d"}

解决方案

Use this one :

.*[A-Za-z0-9].*

It matches at least one alphanumeric character. Doing this, it will take any string that is not only symbols/special chars. It does the output you want, see here : demo

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